如何在 iPhone 应用程序中显示搜索表中的第一个单词

发布于 2024-12-04 00:01:20 字数 475 浏览 4 评论 0原文

嗨，我的 iPhone 应用程序中的每个应用程序都有一个搜索屏幕和一个搜索屏幕。我在搜索栏中有一些条目，例如 sudha、tharanga 和 Womensera（一些杂志），假设如果我们搜索板球特别版，它必须显示相应的杂志，

因此我计划使用如下所示的表格视图数据

sudha  (cricket special, anna hazare special)
tharanga  (footbal special,x special)
womens era (some y special)

，并将数据加载到表视图通过修剪括号 ( ) 之间存在的所有数据，我应该在表视图中显示剩余的数据

，那么我如何修剪字符串，以便它应该删除括号和括号符号中的数据

，以便我的表视图数据应该变成这样

sudha  
tharanga 
womens era

，提前谢谢

原文

hii every one in my iphone app i have a search screen & i have some entries in the search bar like sudha, tharanga and womens era (some magazines ) suppose if we search cricket special, it has to show the respective magazine

so i planned to have the table view data like follows

sudha  (cricket special, anna hazare special)
tharanga  (footbal special,x special)
womens era (some y special)

and while loading data to the table view by trimming the all data which is present between the brackets ( ) and should i display remaining in the table view

so how can i trim the string in such a way that it should remove the data with in brackets and bracket symbols

so that my table view data should become like this

sudha  
tharanga 
womens era

, thanx in advance

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热血少△年 2024-12-11 00:01:20

关于根据您的要求修剪字符串，我想最简单的方法是使用 - (NSArray *)componentsSeparatedByString:(NSString *)separator 方法，如下所示；

NSArray *anArray = [theFullString componentsSeparatedByString:@"("];

假设 theFullString = @"womensera (some yspecial)"，结果数组的第一个元素将是 @"womensera "。我认为这工作正常。

Regarding trimming the string as per your requirement, I guess the simplest way to go about it is to use the - (NSArray *)componentsSeparatedByString:(NSString *)separator method as follows;

NSArray *anArray = [theFullString componentsSeparatedByString:@"("];

Assuming theFullString = @"womens era (some y special)", the resulting arrays first element would be as @"womens era ". I assume this works fine.

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仙女山的月亮 2024-12-11 00:01:20

使用此 nnstring 方法获得所需的结果，

- (NSString *)substringWithRange:(NSRange)range;

或者您可以这样做，首先找到括号位置，

int pointPos = -1;
for(int i=0; i<= [myString length]-1; i++){
    if ([myString characterAtIndex:i] == '(') {
        pointPos = i;
        break;
    }
}

NSString *finalString = [myString substringToIndex:pointPos];

Use this nnstring method to get the desired result,

- (NSString *)substringWithRange:(NSRange)range;

OR you can do that, first find bracket location,

int pointPos = -1;
for(int i=0; i<= [myString length]-1; i++){
    if ([myString characterAtIndex:i] == '(') {
        pointPos = i;
        break;
    }
}

NSString *finalString = [myString substringToIndex:pointPos];

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