Picasa 相册标题编码。不是统一码?

发布于 2024-12-03 23:56:48 字数 947 浏览 0 评论 0原文

我为 Google Picasa 服务编写了一个简单的客户端。我想要的是创建一个包含相册标题名称的文件夹,并将原始照片从服务下载到该文件夹​​。 如果标题中有任何非拉丁字符,我会收到 IOError:

IOError: [Errno 2] 没有这样的文件或目录: '\xd0\x9e\xd1\x81\xd0\xb5\xd0\xbd\xd1\x8c\Autumnal-Equinox.jpg'

代码示例:

import gdata.photos.service
import gdata.media
import os
import urllib2

gd_client = gdata.photos.service.PhotosService()

username = 'cha.com.ua'
albums = gd_client.GetUserFeed(user=username)
for album in albums.entry:
        photos = gd_client.GetFeed(
            '/data/feed/api/user/%s/albumid/%s?kind=photo' % (
                username, album.gphoto_id.text))

        for photo in photos.entry:
            destination = os.path.join(album.title.text, photo.title.text)
            out = open(destination, 'wb')
            out.write(urllib2.urlopen(photo.content.src).read())
            out.close()

我尝试使用 .decode('utf-8') 解码标题,它不起作用。

I wrote a simple client for Googles Picasa service. What I want is to create a folder with albums title name and download original photo from the service to this folder.
If there is any non-latin characters in title I got an IOError:

IOError: [Errno 2] No such file or directory:
'\xd0\x9e\xd1\x81\xd0\xb5\xd0\xbd\xd1\x8c\Autumnal-Equinox.jpg'

Code sample:

import gdata.photos.service
import gdata.media
import os
import urllib2

gd_client = gdata.photos.service.PhotosService()

username = 'cha.com.ua'
albums = gd_client.GetUserFeed(user=username)
for album in albums.entry:
        photos = gd_client.GetFeed(
            '/data/feed/api/user/%s/albumid/%s?kind=photo' % (
                username, album.gphoto_id.text))

        for photo in photos.entry:
            destination = os.path.join(album.title.text, photo.title.text)
            out = open(destination, 'wb')
            out.write(urllib2.urlopen(photo.content.src).read())
            out.close()

I tried to decode the title with .decode('utf-8'), it does't work.

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云醉月微眠 2024-12-10 23:56:48

你说:

@rocksportrocker repr(album.title.text) returns str:
'\xd0\x92\xd0\xb8\xd0\xb4 \xd0\xb8\xd0\xb7 \xd0\xbe\xd0\xba\xd0\xbd\xd0\xb0'

@d-k Yep, I've tried it. The result is the same.
For example repr(album.title.text.encode('utf-8')) returns str:
'\xd0\x92\xd0\xb8\xd0\xb4 \xd0\xb8\xd0\xb7 \xd0\xbe\xd0\xba\xd0\xbd\xd0\xb0'

不可能是真的。如果第一个语句正确,第二个语句将导致:

UnicodeDecodeError: 'ascii' codec can't decode byte 0xd0 in position 0: ordinal not in range(128)

看来您的 str 对象是一个 UTF-8 编码的西里尔字符串:

>>> foo = '\xd0\x92\xd0\xb8\xd0\xb4 \xd0\xb8\xd0\xb7 \xd0\xbe\xd0\xba\xd0\xbd\xd0\xb0'
>>> from unicodedata import name
>>> for uc in foo.decode('utf8'):
...     print "U+%04X" % ord(uc), name(uc)
...
U+0412 CYRILLIC CAPITAL LETTER VE
U+0438 CYRILLIC SMALL LETTER I
U+0434 CYRILLIC SMALL LETTER DE
U+0020 SPACE
U+0438 CYRILLIC SMALL LETTER I
U+0437 CYRILLIC SMALL LETTER ZE
U+0020 SPACE
U+043E CYRILLIC SMALL LETTER O
U+043A CYRILLIC SMALL LETTER KA
U+043D CYRILLIC SMALL LETTER EN
U+0430 CYRILLIC SMALL LETTER A
>>>

而且上面的内容与错误消息中的文本完全不同: '\xd0 \x9e\xd1\x81\xd0\xb5\xd0\xbd\xd1\x8c\Autumnal-Equinox.jpg'

>>> bar =  '\xd0\x9e\xd1\x81\xd0\xb5\xd0\xbd\xd1\x8c\Autumnal-Equinox.jpg'
>>> for uc in bar.decode('utf8'):
...     print "U+%04X" % ord(uc), name(uc)
...
U+041E CYRILLIC CAPITAL LETTER O
U+0441 CYRILLIC SMALL LETTER ES
U+0435 CYRILLIC SMALL LETTER IE
U+043D CYRILLIC SMALL LETTER EN
U+044C CYRILLIC SMALL LETTER SOFT SIGN
U+005C REVERSE SOLIDUS
U+0041 LATIN CAPITAL LETTER A
U+0075 LATIN SMALL LETTER U
U+0074 LATIN SMALL LETTER T
# snipped the remainder

REVERSE SOLIDUS(反斜杠)表示您正在 Windows 上运行。 Windows 就是不理解 UTF-8。输入时将所有文本转换为 Unicode。对所有路径和文件名使用 Unicode。有效的简单示例:

>>> bar =  '\xd0\x9e\xd1\x81\xd0\xb5\xd0\xbd\xd1\x8c.txt'
>>> ubar = bar.decode('utf8')
>>> print repr(ubar)
u'\u041e\u0441\u0435\u043d\u044c.txt'
>>> f = open(ubar, 'wb')
>>> f.write('hello\n')
>>> f.close()
>>> open(ubar, 'rb').read()
'hello\n'

You say:

@rocksportrocker repr(album.title.text) returns str:
'\xd0\x92\xd0\xb8\xd0\xb4 \xd0\xb8\xd0\xb7 \xd0\xbe\xd0\xba\xd0\xbd\xd0\xb0'

and

@d-k Yep, I've tried it. The result is the same.
For example repr(album.title.text.encode('utf-8')) returns str:
'\xd0\x92\xd0\xb8\xd0\xb4 \xd0\xb8\xd0\xb7 \xd0\xbe\xd0\xba\xd0\xbd\xd0\xb0'

This cannot be true. If the first statement is correct, the second will cause:

UnicodeDecodeError: 'ascii' codec can't decode byte 0xd0 in position 0: ordinal not in range(128)

It appears that your str object is a UTF-8 encoded Cyrillic string:

>>> foo = '\xd0\x92\xd0\xb8\xd0\xb4 \xd0\xb8\xd0\xb7 \xd0\xbe\xd0\xba\xd0\xbd\xd0\xb0'
>>> from unicodedata import name
>>> for uc in foo.decode('utf8'):
...     print "U+%04X" % ord(uc), name(uc)
...
U+0412 CYRILLIC CAPITAL LETTER VE
U+0438 CYRILLIC SMALL LETTER I
U+0434 CYRILLIC SMALL LETTER DE
U+0020 SPACE
U+0438 CYRILLIC SMALL LETTER I
U+0437 CYRILLIC SMALL LETTER ZE
U+0020 SPACE
U+043E CYRILLIC SMALL LETTER O
U+043A CYRILLIC SMALL LETTER KA
U+043D CYRILLIC SMALL LETTER EN
U+0430 CYRILLIC SMALL LETTER A
>>>

Also the above is quite unlike the text in the error message: '\xd0\x9e\xd1\x81\xd0\xb5\xd0\xbd\xd1\x8c\Autumnal-Equinox.jpg'

>>> bar =  '\xd0\x9e\xd1\x81\xd0\xb5\xd0\xbd\xd1\x8c\Autumnal-Equinox.jpg'
>>> for uc in bar.decode('utf8'):
...     print "U+%04X" % ord(uc), name(uc)
...
U+041E CYRILLIC CAPITAL LETTER O
U+0441 CYRILLIC SMALL LETTER ES
U+0435 CYRILLIC SMALL LETTER IE
U+043D CYRILLIC SMALL LETTER EN
U+044C CYRILLIC SMALL LETTER SOFT SIGN
U+005C REVERSE SOLIDUS
U+0041 LATIN CAPITAL LETTER A
U+0075 LATIN SMALL LETTER U
U+0074 LATIN SMALL LETTER T
# snipped the remainder

The REVERSE SOLIDUS (backslash) indicates that you are running on Windows. Windows just doesn't grok UTF-8. Convert all your text to Unicode on input. Use Unicode for all paths and filenames. Simple example which works:

>>> bar =  '\xd0\x9e\xd1\x81\xd0\xb5\xd0\xbd\xd1\x8c.txt'
>>> ubar = bar.decode('utf8')
>>> print repr(ubar)
u'\u041e\u0441\u0435\u043d\u044c.txt'
>>> f = open(ubar, 'wb')
>>> f.write('hello\n')
>>> f.close()
>>> open(ubar, 'rb').read()
'hello\n'
~没有更多了~
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