字符串转换中的十六进制值

发布于 2024-12-03 21:18:39 字数 554 浏览 1 评论 0原文

我有一个 C++ 脚本，其中涉及可能的十六进制数字的字符串表示形式。在脚本的后面部分中，我想将这些可能的十六进制数转换为双精度数，以进行以 10 为基数的算术。为了尝试进行此转换，我使用了一个函数。

double MyFunction(string input)
{
double Number;
stringstream ss(input);
ss >> hex >> Number;
return Number;
}

当我的脚本运行时，似乎转换后的字符串仅被视为十进制数。如果原始字符串是“fc”或“b5”，则表示转换后的数字为-9.25596e+061。但如果字符串是“33”（应该是 0x33），它会将其视为十进制 33。我已经尝试过不使用“>> 十六进制”并在转换之前在字符串中添加“0x”前缀（因为编译似乎理解 0xF 就像理解 16 一样），但没有这样的运气。

我知道计算机将所有内容存储为二进制，并且不存储查看数字的基数，但我根本不明白这里出了什么问题。为什么它似乎坚持以 10 为基数读取字符串并忽略任何 AF 实例？

任何帮助将不胜感激。

原文

I have a C++ script which involves string representations of would-be hexadecimal numbers. In a later portion of the script, I would like to convert these would-be hexadecimal numbers into doubles for some arithmetic in base 10. To try to make this conversion, I use a function.

double MyFunction(string input)
{
double Number;
stringstream ss(input);
ss >> hex >> Number;
return Number;
}

When my script runs, it seems the resulting converted string is only considered as a decimal number. If the original string was "fc" or "b5", it says the converted number is -9.25596e+061. But if the string was "33" (which is supposed to be 0x33), it views it as decimal 33. I have tried it without the ">> hex" and with adding a "0x" prefix to the string before conversion (since the compile seems to understand 0xF just as it would 16), but no such luck.

I understand the computer stores everything as binary and that the base a number is viewed at is not stored, but I simply do not understand what is wrong here. Why does it seemingly insist upon reading the string in base 10 and disregarding any instance of A-F?

Any help will be appreciated.

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大姐，你呐 2024-12-10 21:18:39

十六进制操纵器仅适用于 int 等整数类型。首先将十六进制字符串输入整数，然后将其转换为双精度数：

double MyFunction(string input)
{
    int Number; // Notice now Number is an integer
    stringstream ss(input);
    ss >> hex >> Number; 
    return Number; // This should convert Number to a double via promotion
}

The hex manipulator only works for integral types like int. First input the hexadecimal string into an integer and then convert that to a double:

double MyFunction(string input)
{
    int Number; // Notice now Number is an integer
    stringstream ss(input);
    ss >> hex >> Number; 
    return Number; // This should convert Number to a double via promotion
}

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