PHPUnit 在带有命名空间的 Netbeans 中失败

Question

我有：PHP 5.3.8、PHPUnit 3.5.15、Netbeans 7.0.1

在使用 Netbeans 的标准示例进行 PHPUnit 测试时，它运行得很好。 通过仅添加“命名空间测试；”我收到错误消息 Calculator.php 不是文件也不是目录。如何解决这个问题呢？ （我想在我的项目中使用命名空间声明）

要测试的类：

namespace test;

class Calculator {

/**
 * @assert (0, 0) == 0
 * @assert (0, 1) == 1
 * @assert (1, 0) == 1
 * @assert (1, 1) == 2
 * @assert (1, 2) == 4
 */
public function add($a, $b) {
    return $a + $b;
}

}

?>

单元测试：

require_once dirname(__FILE__) . '/../Calculator.php';

/**
 * Test class for Calculator.
 * Generated by PHPUnit on 2011-09-11 at 00:52:24.
 */
class CalculatorTest extends PHPUnit_Framework_TestCase {

/**
 * @var Calculator
 */
protected $object;

/**
 * Sets up the fixture, for example, opens a network connection.
 * This method is called before a test is executed.
 */
protected function setUp() {
    $this->object = new Calculator;
}

/**
 * Tears down the fixture, for example, closes a network connection.
 * This method is called after a test is executed.
 */
protected function tearDown() {

}

/**
 * Generated from @assert (0, 0) == 0.
 */
public function testAdd() {
    $this->assertEquals(
            0, $this->object->add(0, 0)
    );
}

/**
 * Generated from @assert (0, 1) == 1.
 */
public function testAdd2() {
    $this->assertEquals(
            1, $this->object->add(0, 1)
    );
}

/**
 * Generated from @assert (1, 0) == 1.
 */
public function testAdd3() {
    $this->assertEquals(
            1, $this->object->add(1, 0)
    );
}

/**
 * Generated from @assert (1, 1) == 2.
 */
public function testAdd4() {
    $this->assertEquals(
            2, $this->object->add(1, 1)
    );
}

/**
 * Generated from @assert (1, 2) == 4.
 */
public function testAdd5() {
    $this->assertEquals(
            4, $this->object->add(1, 2)
    );
}

}

?>

Answer 1

@Tomasz 的答案当然是正确的。作为一个小插件：

据我了解，将测试放在与生产类相同的命名空间中已成为常见做法。

namespace test;
require_once dirname(__FILE__) . '/../Calculator.php';

class CalculatorTest extends \PHPUnit_Framework_TestCase {

然后你可以继续使用

$this->object = new Calculator:

Answer 2

了解如何在代码中使用命名空间类。您需要创建计算器类实例，而不是：

$this->object = new Calculator;

但是：

$this->object = new \test\Calculator;

我假设该类已加载。如果没有看到您的自动加载器或正确的文件路径。