从数据文件中删除选定的行 - 第 2 部分
这是之前的讨论之后：（从数据文件中删除选定的行）
我有尝试遵循 Fredirk 和 Glenn Jackman 提出的想法，我得出如下代码，仅在这对数字与特定的 creteria 匹配时才打印行。
当我执行代码时，有输出，但它打印所有行，而不是仅打印特定行。
#!/usr/bin/awk -f
BEGIN {
i=0
for (n=1; n<=8; n++) set[i++] = n;
for (n=57; n<=64; n++) set[i++] = n;
for (n=9; n<=49; n+=8) {set[i++] = n; set[i++] = n+7};
}
/^|/{
split($3, res1, "@"); split($6, res2, "@"); #print res1[1], res2[1]
if ( (res1[1] in set) == (res2[1] in set) );
{
print;
next;
}
}
如果有错误的话，谁能帮忙找出错误吗？我可以弄清楚为什么它没有得到。 谢谢。
This is following previous discussion: ( deleting selected lines from data file)
I have tried follow the idea addressed by Fredirk and Glenn Jackman and I come out with the code as below to only print the lines if the pair of numbers are matching specific creteria.
When I execute the code, there is output but it prints all the lines instead only the specific ones.
#!/usr/bin/awk -f
BEGIN {
i=0
for (n=1; n<=8; n++) set[i++] = n;
for (n=57; n<=64; n++) set[i++] = n;
for (n=9; n<=49; n+=8) {set[i++] = n; set[i++] = n+7};
}
/^|/{
split($3, res1, "@"); split($6, res2, "@"); #print res1[1], res2[1]
if ( (res1[1] in set) == (res2[1] in set) );
{
print;
next;
}
}
Could anyone help to find any bug if there is one? I can figure out why it is not getting.
Thank you.
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if命令后面有一个杂散的分号。如果该条件为真，则您什么也不做。然后打印每一行。There's a stray semi-colon after the
ifcommand. You do nothing if that condition is true. And then you print each line.