如何使用参数化构造函数运行 junit

发布于 2024-12-03 18:42:21 字数 391 浏览 1 评论 0原文

我必须从命令行运行 junit 测试，团队中的一个人创建了如下所示的 junit 类：

public Test extends TestCore
{
   String some;

   public Test(String some)
   {
      this.some = some;
   }
//some test here
}

这项工作在 eclipse 中进行，但不是从命令行进行。执行此类文件的结果给了我如下错误：

Test class should have exactly one public zero-argument constructor.

有人可以帮助我吗？

雅罗斯瓦夫干杯。

原文

I have to run junit test from command line and one of the guy in the team created junit classes like below:

public Test extends TestCore
{
   String some;

   public Test(String some)
   {
      this.some = some;
   }
//some test here
}

this work from the eclipse but doesn't from command line.
The result of execution this kind of file gave me error like below:

Test class should have exactly one public zero-argument constructor.

Anyone could help me?

Cheers Jaroslaw.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

短暂陪伴 2024-12-10 18:42:22

Eclipse 使用不同的测试运行器。也许参数化构造函数是由 TestCore 作为参数化测试引起的，例如：

@RunWith(Parameterized.class)
public class TestCore {
  String someThatWillBeHidden;

  public TestCore(String some) {
    this.someThatWillBeHidden = some;
  }

  @Parameters
  public static List<Object[]> data() {
    Object[][] data = new Object[][] { {"Hello"}, {" "}, {"world"}}; 
    return Arrays.asList(data);
  }

//some test here

}

那么您使用的是哪个版本的 junit？

Eclipse uses a different testrunner. Maybe the parameterized constructors are caused by TestCore being a parameterized test, e.g. like this:

@RunWith(Parameterized.class)
public class TestCore {
  String someThatWillBeHidden;

  public TestCore(String some) {
    this.someThatWillBeHidden = some;
  }

  @Parameters
  public static List<Object[]> data() {
    Object[][] data = new Object[][] { {"Hello"}, {" "}, {"world"}}; 
    return Arrays.asList(data);
  }

//some test here

}

So which version of junit are you using?

回复收藏 0 原文

~没有更多了~