如何访问我的 Android 程序中的联系人

Question

我正在制作一个短信应用程序，并且想要访问我的 Android 应用程序中的联系人 。

我想访问联系人，就像他们在实际联系人列表中一样。选择后，我需要返回到我的活动，在其中我可以向该人发送短信。或者是否可以访问存储联系人的数据库？

我的代码如下所示：

String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
String name = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME)); 
String no = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER));

我的 LogCat 如下所示：

09-07 12:46:15.458: DEBUG/AndroidRuntime(473): Shutting down VM
09-07 12:46:15.458: WARN/dalvikvm(473): threadid=1: thread exiting with uncaught exception (group=0x40015560)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): FATAL EXCEPTION: main
09-07 12:46:15.478: ERROR/AndroidRuntime(473): java.lang.RuntimeException: Failure delivering result ResultInfo{who=null, request=0, result=-1, data=Intent { dat=content://com.android.contacts/contacts/lookup/0r1-512D3F3D533B/1 flg=0x1 (has extras) }} to activity {task.list/task.list.Msgactivity}: java.lang.IllegalArgumentException: column 'data1' does not exist
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.app.ActivityThread.deliverResults(ActivityThread.java:2532)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.app.ActivityThread.handleSendResult(ActivityThread.java:2574)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.app.ActivityThread.access$2000(ActivityThread.java:117)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.app.ActivityThread$H.handleMessage(ActivityThread.java:961)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.os.Handler.dispatchMessage(Handler.java:99)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.os.Looper.loop(Looper.java:123)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.app.ActivityThread.main(ActivityThread.java:3683)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at java.lang.reflect.Method.invokeNative(Native Method)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at java.lang.reflect.Method.invoke(Method.java:507)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:839)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:597)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at dalvik.system.NativeStart.main(Native Method)
09-07 12:46:15.478: ERROR/AndroidRuntime(473): Caused by: java.lang.IllegalArgumentException: column 'data1' does not exist
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.database.AbstractCursor.getColumnIndexOrThrow(AbstractCursor.java:314)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.database.CursorWrapper.getColumnIndexOrThrow(CursorWrapper.java:99)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at task.list.Msgactivity.onActivityResult(Msgactivity.java:99)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.app.Activity.dispatchActivityResult(Activity.java:3908)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     at android.app.ActivityThread.deliverResults(ActivityThread.java:2528)
09-07 12:46:15.478: ERROR/AndroidRuntime(473):     ... 11 more
09-07 12:46:15.489: WARN/ActivityManager(61):   Force finishing activity task.list/.Msgactivity

谁能帮助我？

Answer 1

使用此代码选择联系人：

 Button button = (Button)findViewById(R.id.pickcontact);

    button.setOnClickListener(new OnClickListener() 
        {
            @Override
            public void onClick(View v) 
            {
                 Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
                 startActivityForResult(intent, PICK_CONTACT);
             }
         });



    @Override public void onActivityResult(int reqCode, int resultCode, Intent data){ super.onActivityResult(reqCode, resultCode, data);

    switch(reqCode)
    {
       case (PICK_CONTACT):
         if (resultCode == Activity.RESULT_OK)
         {
             Uri contactData = data.getData();
             Cursor c = managedQuery(contactData, null, null, null, null);
          if (c.moveToFirst())
          {
          String id = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts._ID));

          String hasPhone =
          c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));

          if (hasPhone.equalsIgnoreCase("1")) 
          {
         Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null, 
          ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id,null, null);
            phones.moveToFirst();
            String cNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
           // Toast.makeText(getApplicationContext(), cNumber, Toast.LENGTH_SHORT).show();
            setCn(cNumber);
          }
         }
       }
    }
   }

Answer 2

检查以下链接：

如何调用 Android 联系人列表？

如何从android中的本机电话簿获取联系人

如何在 Android 中获取联系人的所有详细信息

如何从 Android 获取名字和姓氏联系人？

如何将联系人从电话簿导入到我们的应用程序

Android 联系人提取

如何获取所有Android联系人但没有SIM 卡上的内容

http://mobile.tutsplus.com/tutorials/android/android-essentials-using-the-contact-picker/

Answer 3

试试这个代码。 这会将所有联系人存储在 ArrayList 中。

ArrayList<HashMap<String,String>> contactData=new ArrayList<HashMap<String,String>>();
ContentResolver cr = getContentResolver();
 Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
 while (cursor.moveToNext()) {
     try{
     String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID)); 
     String name=cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
     String hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)); 
     if (Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
         Cursor phones = getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId, null, null);
         while (phones.moveToNext()) { 
             String phoneNumber = phones.getString(phones.getColumnIndex( ContactsContract.CommonDataKinds.Phone.NUMBER));
             HashMap<String,String> map=new HashMap<String,String>();
             map.put("name", name);
             map.put("number", phoneNumber);
             contactData.add(map);
         } 
         phones.close(); 
     }
 }catch(Exception e){}
 }

如果您想存储特定联系人，请使用 if 条件，

Answer 4

我可以使用 @Balaji.K 的示例进行一些修改。我遇到的主要问题是

while (cursor.moveToNext()) {

会跳过第一个结果。

我还想建立一个电话号码列表，如果没有电话号码被标记为“移动”，用户可以从中进行选择。我还传递了一个名称进行搜索（在本例中替换为变量），但是可以修改此代码以通过将“selection”和“selection_args”替换为 null 并迭代“contacts”中的所有内容来构建一个集合，就像我为“电话”。这是我最终得到的结果（在 Kotlin 中）：

val selection = "lower(${ContactsContract.Contacts.DISPLAY_NAME_PRIMARY}) LIKE ?"
val selectionArgs = arrayOf("<SEARCH_TERM>")
selectionArgs[0] = "%<SEARCH_TERM>%"

// Query contacts for someone with a matching name
val contacts = contentResolver.query(ContactsContract.Contacts.CONTENT_URI,
        null, selection, selectionArgs, null)
contacts!!.moveToFirst()
if (contacts.count > 1) {
    // TODO: Disambiguate and move to the correct position
}
val contactId = contacts.getString(contacts.getColumnIndex(
        ContactsContract.Contacts._ID))

// Check if contact has at least one phone number
if (contacts.getString(contacts.getColumnIndex(
                ContactsContract.CommonDataKinds.Phone.HAS_PHONE_NUMBER)) == "1") {

    val sel = "${ContactsContract.CommonDataKinds.Email.CONTACT_ID} = ?"
    val selArgs = arrayOf(name)
    val sort = "${ContactsContract.CommonDataKinds.Email.LAST_TIME_CONTACTED} DESC"
    selArgs[0] = contactId

    val phones = contentResolver.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, sel, selArgs, sort)
    phones!!.moveToFirst()

    // Iterate through phone numbers if multiple
    if (phones.count > 1) {
        val phoneNumbers = mutableMapOf<Int, ContactData>()
        var loop = true
        var mobileIndex: Int? = null
        while (loop) {
            val phoneType = phones.getInt(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE))
            val phoneName = ContactsContract.CommonDataKinds.Phone.getTypeLabel(resources, phoneType, null).toString()
            phoneNumbers[phones.position] = ContactData(phoneName, phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)))
            // Remember what position the mobile number was in
            if (phoneType == ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE) {
                mobileIndex = phones.position
            }
            loop = phones.moveToNext()
        }
        phones.moveToPosition(mobileIndex)
    }
}