XDocument 的反序列化不起作用
我有这个代码:
[Serializable]
[XmlRoot("ISO_CCY_CODES")]
public class IsoCurrencyCodes
{
public IsoCurrencyCodes()
{
IsoCodes = new List<IsoCurrencyCode>();
}
public IsoCurrencyCodes(List<IsoCurrencyCode> isoCodes)
{
IsoCodes = isoCodes;
}
[XmlArrayItem("ISO_CURRENCY")]
public List<IsoCurrencyCode> IsoCodes { get; set; }
public static IEnumerable<IsoCurrencyCode> Get()
{
var doc = XDocument.Parse(XmlStringIsoCodes.XmlSource.Replace("\r\n", ""));
var res = doc.Deserialize<IsoCurrencyCodes>();
return res.IsoCodes;
}
}
[Serializable]
[XmlRoot("ISO_CURRENCY")]
public class IsoCurrencyCode
{
public IsoCurrencyCode()
{
}
[XmlElement(ElementName = "ENTITY")]
public string Entity { get; set; }
[XmlElement(ElementName = "CURRENCY")]
public string Currency { get; set; }
[XmlElement(ElementName = "ALPHABETIC_CODE")]
public string Alpha_Code3 { get; set; }
[XmlElement(ElementName = "NUMERIC_CODE")]
public int NumCode { get; set; }
[XmlElement(ElementName = "MINOR_UNIT")]
public string MinorUnit { get; set; }
}
这个代码,用于反序列化:
public static XDocument Serialize<T>(this T source)
{
var ser = new XmlSerializer(source.GetType());
var sb = new StringBuilder();
using (var writer = new StringWriter(sb))
{
ser.Serialize(writer, source);
}
return XDocument.Parse(sb.ToString());
}
public static T Deserialize<T>(this XDocument xmlDocument)
{
var xmlSerializer = new XmlSerializer(typeof (T));
using (var reader = xmlDocument.CreateReader())
return (T) xmlSerializer.Deserialize(reader);
}
这是 XML 源
但是反序列化不起作用。请帮忙。 谢谢!
I have this code:
[Serializable]
[XmlRoot("ISO_CCY_CODES")]
public class IsoCurrencyCodes
{
public IsoCurrencyCodes()
{
IsoCodes = new List<IsoCurrencyCode>();
}
public IsoCurrencyCodes(List<IsoCurrencyCode> isoCodes)
{
IsoCodes = isoCodes;
}
[XmlArrayItem("ISO_CURRENCY")]
public List<IsoCurrencyCode> IsoCodes { get; set; }
public static IEnumerable<IsoCurrencyCode> Get()
{
var doc = XDocument.Parse(XmlStringIsoCodes.XmlSource.Replace("\r\n", ""));
var res = doc.Deserialize<IsoCurrencyCodes>();
return res.IsoCodes;
}
}
[Serializable]
[XmlRoot("ISO_CURRENCY")]
public class IsoCurrencyCode
{
public IsoCurrencyCode()
{
}
[XmlElement(ElementName = "ENTITY")]
public string Entity { get; set; }
[XmlElement(ElementName = "CURRENCY")]
public string Currency { get; set; }
[XmlElement(ElementName = "ALPHABETIC_CODE")]
public string Alpha_Code3 { get; set; }
[XmlElement(ElementName = "NUMERIC_CODE")]
public int NumCode { get; set; }
[XmlElement(ElementName = "MINOR_UNIT")]
public string MinorUnit { get; set; }
}
And this code, for deserialization:
public static XDocument Serialize<T>(this T source)
{
var ser = new XmlSerializer(source.GetType());
var sb = new StringBuilder();
using (var writer = new StringWriter(sb))
{
ser.Serialize(writer, source);
}
return XDocument.Parse(sb.ToString());
}
public static T Deserialize<T>(this XDocument xmlDocument)
{
var xmlSerializer = new XmlSerializer(typeof (T));
using (var reader = xmlDocument.CreateReader())
return (T) xmlSerializer.Deserialize(reader);
}
This is the XML source
But deserialization doesn't work. Please help.
Thanks!
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我相信只有当您有一个用于所有项目的集合元素位于下面时,您才想使用 XMLArray。例如,这里可能是 ISO_CURRENCIES。我假设您在这种情况下无法更改源,因此只需使用它即可:
您应该会发现它有效。
此外,如果您发现在正确获取反序列化类方面还有其他问题,您可以从 XML 自动生成它们,然后您可以查看创建的代码:
这将创建 source.cs,然后您可以使用它在您的项目中使用或适应您自己的用途。
进一步说明,您会发现不能将
int
用于 Minor_Unit,因为它可以为 null(请查看 ANTARCTICA)。您不能直接反序列化为 int?,因此您必须将其设为字符串或通过另一个属性,请查看 此问题了解更多信息。I believe you only want to use XMLArray if you have a collection element for all of the items to sit underneath. For example here it could be ISO_CURRENCIES. I'm assuming you can't change the source in this case, so just use this instead:
You should find that works.
Additionally, if you find you have further problems in getting the deserialization classes right, you can have them autogenerated for you from the XML and then you can take a look at the code that is created:
This will create source.cs which you can then use in your project or adapt for your own uses.
As a further note, you'll find you can't use
int
for Minor_Unit as it's nullable (look at ANTARCTICA). You can't deserialize straight to an int?, so you'll either have to make it a string or go via another property, look at this question for more information.