Actionscript 2.0 XML 按名称获取子项

Question

现在我正在将一些 AS3.0 应用程序移植到 AS2.0（不要问我为什么:)） 在 AS3.0 中，我以简单的方式获取 xml 中名为“x”的子节点：

xml.child(“x”)。

如何在 AS2.0 中获取“x”节点？ 当然，我可以编写一个循环来枚举 xml 的子级并将它们的名称与“x”进行比较。 但我希望有一个更简单的方法......

Answer 1

不是 100% 确定，但使用 XPath API 应该更容易（PDF链接）在as2中而不是默认的节点循环。应该还有一些被遗忘的资源 在网络上。

Answer 2

解析另存为 XML 2003 的 Excel 文件
（另存为xml后，用记事本打开并删除前两行）

// XML
var main_xml:XML = new XML();
main_xml.ignoreWhite = true;
main_xml.load(_global.path + "main.xml"+_global.randomprm)
main_xml.onLoad = function(success) {
    var s:String = xmlValueOnPageByColTitleAndRow("your_worksheet_title", "cell_value_in_any_row_in_interested_column_OR_column_title_in_table", 2); // 2 - row number in table
    trace(s);
};

function xmlValueOnPageByColTitleAndRow(PageName:String, ColTitle:String, Row:Number) {
    var worksheet:XMLNode = xmlNodeByNameWithValue(main_xml.firstChild, "Worksheet", PageName);
    var column = xmlColumnByValue(worksheet, ColTitle);
    var rowNode:XMLNode = xmlNodeByNameWithOrder(worksheet, "Row", Row);
    var cell:XMLNode = xmlNodeByNameWithOrder(rowNode, "Cell", column);
    return cell.firstChild.firstChild.nodeValue;
}

function xmlColumnByValue(node:XMLNode, Value:String) {
    if (node.firstChild.nodeName == "Cell") {
        var n = 0;
        for (var childnode:XMLNode = node.firstChild; childnode != null; childnode = childnode.nextSibling, n++) {
            if (childnode.firstChild.firstChild.nodeValue == Value) return n;
        }
    } else 
    for (var childnode:XMLNode = node.firstChild; childnode != null; childnode = childnode.nextSibling) {
        res = xmlColumnByValue(childnode, Value); 
        if (res > -1) return res;
    }
    return -1;
}

function xmlNodeByNameWithOrder(node:XMLNode, Name:String, Order:Number) {
    var n = 0;
    for (var childnode:XMLNode = node.firstChild; childnode != null; childnode = childnode.nextSibling)
        if (childnode.nodeName == Name) {
            n++;
            if (n == Order) return childnode;
        }
    for (var childnode:XMLNode = node.firstChild; childnode != null; childnode = childnode.nextSibling) {
        finded = xmlNodeByNameWithOrder(childnode, Name, Order); 
        if (finded != NULL) return finded;
    }
    return NULL;
}

function xmlHasValue(node:XMLNode, Value:String) {
    for (attr in node.attributes) {
        if (node.attributes[attr] == Value) return true;
    }
    return false;
}

function xmlNodeByNameWithValue(node:XMLNode, Name:String, Value:String) {
    if (node.nodeName == Name) {
        if (xmlHasValue(node, Value)) 
            return node;
        else 
            return null;
    } else {
        for (var childnode:XMLNode = node.firstChild; childnode != null; childnode = childnode.nextSibling) {
            finded = xmlNodeByNameWithValue(childnode, Name, Value); 
            if (finded != NULL) return finded;
        }
    }
    return NULL;
}

var depth = 0;
var str = "";
function traceAllChilds(node:XMLNode) {
    depth++;
    str = ""; for (var i=0; i<depth; i++) str = str + " ";
    if (node.nodeValue) trace(str + node.nodeName + " = " + node.nodeValue);
        else trace(str + node.nodeName);
    for (attr in node.attributes)
        trace (str + " [" + attr + " = " + node.attributes[attr]+"]");
    for (var childnode:XMLNode = node.firstChild; childnode != null; childnode = childnode.nextSibling)
        traceAllChilds(childnode); 
    str = ""; for (var i=0; i<depth; i++) str = str + " ";
    trace(str+""+ node.nodeName);
    depth--;
    return true;
}