拖放而不删除 UIButton

Question

我正在 iPhone 应用程序中实现拖放系统。到目前为止，我成功实现了可拖动按钮，并且工作正常。这是我的代码：

首先，我将操作分配给按钮：

[button addTarget:self action:@selector(imageMoved:withEvent:) forControlEvents:UIControlEventTouchDragInside];

然后，我创建拖动：

- (IBAction) imageMoved:(id) sender withEvent:(UIEvent *) event
{
    NSLog(@"moved");
    CGPoint point = [[[event allTouches] anyObject] locationInView:self.view];
    UIControl *control = sender;
    control.center = point;
}

但是，我想要实现的是被拖动的按钮不会从原来的位置删除。所以我想到了一个解决方案，即创建一个与第一个类似的新按钮，然后移动这个新创建的按钮。但我在实现最后一部分时遇到了麻烦。 有什么帮助吗？非常感谢！

Answer 1

- (IBAction) imageMoved:(id) sender withEvent:(UIEvent *) event {
    NSLog(@"moved");          

    CGPoint point = [[[event allTouches] anyObject] locationInView:self.view];

    if (![self.view viewWithTag:11]) {

        NSData *archivedData = [NSKeyedArchiver archivedDataWithRootObject:(UIButton*)sender];                

        UIButton *anotherButton =(UIButton*) [NSKeyedUnarchiver unarchiveObjectWithData:archivedData];

        anotherButton.tag = 11;    


        UIImage *senderImage=[(UIButton *)sender imageForState:UIControlStateNormal];




        CGImageRef cgImage = [senderImage CGImage];


        UIImage *copyOfImage = [[UIImage alloc] initWithCGImage:cgImage];



        [anotherButton setImage:copyOfImage forState:UIControlStateNormal];

        [self.view addSubview:anotherButton];
    }

    [self.view viewWithTag:11].center = point;
}

Answer 2

要消除限制，您可以在原始按钮上添加两个事件，如下所示：

[button addTarget:self action:@selector(imageMoved:withEvent:) forControlEvents:UIControlEventTouchDragInside];
[button addTarget:self action:@selector(imageMoved:withEvent:) forControlEvents:UIControlEventTouchDragOutside];

这样，当您退出当前视图（您的按钮）的边界时，该事件也会触发，并且您将能够将新按钮移动到周围超级视图。