为什么我无法在 Node.js 中对该 URL 进行 url 编码？

发布于 2024-12-03 09:23:19 字数 331 浏览 0 评论 0原文

$node
querystring = require('querystring')
var dict = { 'q': 'what\'s up' };
var url = 'http://google.com/?q=' + querystring.stringify(dict);
url = encodeURIComponent(url);
console.log(url);

结果是这样的：

"http://google.com/?q=q=what's%20up"

注意单引号的编码不正确。 Node.js 模块有问题吗？

原文

$node
querystring = require('querystring')
var dict = { 'q': 'what\'s up' };
var url = 'http://google.com/?q=' + querystring.stringify(dict);
url = encodeURIComponent(url);
console.log(url);

The result is this:

"http://google.com/?q=q=what's%20up"

Notice how the single quote is not encoded correctly. Is there something wrong with the node.js module?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

茶底世界 2024-12-10 09:23:19

URI 查询中允许以明文形式使用 '。以下是相应的根据 RFC 3986 的 URI 查询的生成规则：

query = *( pchar / "/" / "?" )
pchar = 未保留 / pct 编码 / 子分隔符 / ":" / "@"
未保留=字母/数字/“-”/“。” /“_”/“~”
pct 编码 = "%" HEXDIG HEXDIG
子分隔符=“！” /“$”/“&” /“'”/“(”/“)”
              /“*”/“+”/“，”/“；” /“=”

正如您所看到的，sub-delims 包含一个普通的 '。所以结果是有效的。

The ' is allowed in plain in the URI query. Here are the corresponding production rules for the URI query as per RFC 3986:

query         = *( pchar / "/" / "?" )
pchar         = unreserved / pct-encoded / sub-delims / ":" / "@"
unreserved    = ALPHA / DIGIT / "-" / "." / "_" / "~"
pct-encoded   = "%" HEXDIG HEXDIG
sub-delims    = "!" / "quot; / "&" / "'" / "(" / ")"
              / "*" / "+" / "," / ";" / "="

As you can see, sub-delims contains a plain '. So the result is valid.

回复收藏 0 原文

少女的英雄梦 2024-12-10 09:23:19

它编码正确，如果您手动在 google Sear 字段中输入相同的查询，您将获得此地址：

http://www.google.cz/#hl=cs&cp=8&gs_id=u&xhr=t&q=what's+up&pf=p&sclient=psy&site=&source=hp&pbx=1&oq=what's+u&aq=0&aqi=g5&aql=&gs_sm=&gs_upl=&bav=on.2,or.r_gc.r_pw.&fp=792ecf51920895b2&biw=1276&bih=683

请注意 &q=what's+up& 部分

和 encodeURIComponent 是不是 Node.js 模块，而是标准 javascript 库的一部分

https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/encodeURIComponent

手动解决方法：

$node
querystring = require('querystring')
var dict = { 'q': 'what\'s up' };
var url = 'http://google.com/?q=' + querystring.stringify(dict);
url = encodeURIComponent(url);
url = url.replace(/'/g,"%27");

it is encoded correctly, if you type the same query into google sear field manually you will get this address:

http://www.google.cz/#hl=cs&cp=8&gs_id=u&xhr=t&q=what's+up&pf=p&sclient=psy&site=&source=hp&pbx=1&oq=what's+u&aq=0&aqi=g5&aql=&gs_sm=&gs_upl=&bav=on.2,or.r_gc.r_pw.&fp=792ecf51920895b2&biw=1276&bih=683

note that &q=what's+up& part

and encodeURIComponent is not a Node.js module, but part of standard javascript library

https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/encodeURIComponent

manual workaround:

$node
querystring = require('querystring')
var dict = { 'q': 'what\'s up' };
var url = 'http://google.com/?q=' + querystring.stringify(dict);
url = encodeURIComponent(url);
url = url.replace(/'/g,"%27");

回复收藏 0 原文

~没有更多了~