YAJL - iOS/iPhone 上的 JSON

发布于 2024-12-03 06:34:47 字数 956 浏览 1 评论 0原文

在我的 iPhone 应用程序中，我尝试使用 JSON 库 (YAJL) 创建一个类似于以下格式的 JSON 字符串：

{"user": 
  {"name":"Jon", "username":"jon22", "password":"passw@rd", "email":"[email protected]"}
}

但我无法弄清楚创建此字符串的 YAJL 方法。

我已尝试以下操作：

 NSArray *params = [NSArray arrayWithObjects:@"Jon", @"jon22", @"passw@rd", @"[email protected]", nil];
 NSArray *keys = [NSArray arrayWithObjects:@"name", @"username", @"password", @"email", nil];

 NSDictionary *userDictionary = [NSDictionary dictionaryWithObjects:params forKeys:keys];
 NSString *JSONString = [userDictionary yajl_JSONString];

但是，返回的字符串未包装在外部“用户”中。 如何使用 YAJL 创建这个 json 字符串？ 有人有这方面的经验吗？？？

非常感谢，布雷特

原文

In my iPhone app, I am trying to use the JSON library (YAJL) to create a JSON string that looks like the following format:

{"user": 
  {"name":"Jon", "username":"jon22", "password":"passw@rd", "email":"[email protected]"}
}

But I can't figure out the YAJL methods to create this.

I have tried the following:

 NSArray *params = [NSArray arrayWithObjects:@"Jon", @"jon22", @"passw@rd", @"[email protected]", nil];
 NSArray *keys = [NSArray arrayWithObjects:@"name", @"username", @"password", @"email", nil];

 NSDictionary *userDictionary = [NSDictionary dictionaryWithObjects:params forKeys:keys];
 NSString *JSONString = [userDictionary yajl_JSONString];

However, the returned string is not wrapped in the outside "user".
How can I use YAJL to create this json string? Does anyone have experience with this???

Many thanks,
Brett

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夜血缘 2024-12-10 06:34:47

我不使用 YAJL，而是使用 SBJSON，苹果也在 iOS 中使用它。 ..

无论如何，库的行为正确：您没有创建“用户”字典！

你需要做一些类似的事情：

NSDictionary *serialize = [NSDictionary dictionaryWithObject:userDictionary forKey:@"user"];

然后“JSON-ize”这个。

这是因为当您在 userDictionary 上调用 -yajl_JSONString 时，您正在使用 userDictionary 作为“根对象”。如果你想将它包装在另一个字典中，你需要明确地这样做。

I don't use YAJL, but SBJSON, which is the one Apple uses in iOS too...

Anyway, the library is behaving correctly: you're not creating an "user" dictionary!

You need to do something like:

NSDictionary *serialize = [NSDictionary dictionaryWithObject:userDictionary forKey:@"user"];

And then "JSON-ize" this one.

This is because when you call -yajl_JSONString on userDictionary, you are using userDictionary as your "root object". If you want to wrap this inside another dictionary, you need to explicitly do so.

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