MySQL:计算两个字段

发布于 2024-12-03 04:38:41 字数 526 浏览 3 评论 0原文

我有一张看起来像这样的表:

Pizza  ----|| Topping 
====================
Cheese--||    Olives
====================
Ham-----     || Tuna
====================
Cheese-- || Olives
====================
Cheese-- || Tuna
====================

我想获得每种类型的披萨的数量,所以在上面的表格中会有一个火腿披萨和2个奶酪披萨(因为奶酪+橄榄是重复的,应该只计算在内)一次)。基本上,我需要计算每两个相等元素的每一行并按披萨分组。

该查询的结果应该是:

Pizza  ----|| Count
====================
Cheese--||    2
====================
Ham-----     || 1
====================

谢谢!

I have a table that looks like this:

Pizza  ----|| Topping 
====================
Cheese--||    Olives
====================
Ham-----     || Tuna
====================
Cheese-- || Olives
====================
Cheese-- || Tuna
====================

I would like to obtain the number of pizzas of each type, so in the table above there would be one ham pizza, and 2 cheese pizzas (since cheese+olives is repeated and should be counted only once). Basically, I need to count each row for each two equal elements and group by pizza.

The result from that query should be:

Pizza  ----|| Count
====================
Cheese--||    2
====================
Ham-----     || 1
====================

Thanks!

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评论(2

失退 2024-12-10 04:38:41
select Pizza, count( distinct Topping) as cnt
from your_pizza_table
group by Pizza
order by cnt desc;
select Pizza, count( distinct Topping) as cnt
from your_pizza_table
group by Pizza
order by cnt desc;
稀香 2024-12-10 04:38:41

试试这个

SELECT pizza, count(distinct pizza,topping) FROM test GROUP BY pizza;

Try this

SELECT pizza, count(distinct pizza,topping) FROM test GROUP BY pizza;
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