获取日期,分解,使用数据选择
我设置了三个变量,$date_legible
(格式为F jS, Y
,即2011年1月1日),$date_timestamp
(self -explanatory)和 $date_normal
(格式为 YYYY-MM-DD)
我有三个选择字段:
<select name="date_mo">
<option value="01">January</option>
<option value="02">February</option>
<option value="03">March</option>
<option value="04">April</option>
<option value="05">May</option>
<option value="06">June</option>
<option value="07">July</option>
<option value="08">August</option>
<option value="09">September</option>
<option value="10">October</option>
<option value="11">November</option>
<option value="12">December</option>
</select>
<select name="date_dy">
<option value="01">1</option>
<option value="02">2</option>
<option value="03">3</option>
<option value="04">4</option>
<option value="05">5</option>
<option value="06">6</option>
<option value="07">7</option>
<option value="08">8</option>
<option value="09">9</option>
<option value="10">10</option>
<option value="11">11</option>
<option value="12">12</option>
<option value="13">13</option>
<option value="14">14</option>
<option value="15">15</option>
<option value="16">16</option>
<option value="17">17</option>
<option value="18">18</option>
<option value="19">19</option>
<option value="20">20</option>
<option value="21">21</option>
<option value="22">22</option>
<option value="23">23</option>
<option value="24">24</option>
<option value="25">25</option>
<option value="26">26</option>
<option value="27">27</option>
<option value="28">28</option>
<option value="29">29</option>
<option value="30">30</option>
<option value="31">31</option>
</select>
<select name="date_yr">
<?php for($year=$curryear;$year<$curryear+51;$year++){ ?>
<option value="<?php echo $year; ?>"><?php echo $year; ?></option>
<?php } ?>
</select>
我知道我想转换时间戳,但我最终需要分解输出对于 $month
、$day
和 $year
。问题是我不知道如何检查对值的选择并自动选择正确的选项。
有人可以帮忙吗?谢谢!
更新
我现在多了一个变量,因为我让用户从前端提交,而重力表单以 YYYY-MM-DD
形式提交。
在深入研究已经发布的解决方案之前(顺便谢谢你们[和女孩们]),这里有更多信息:
我正在运行 WordPress,并且具有如上所述的三个自定义字段。当用户从前端提交帖子时,唯一填写的自定义字段是 $date_normal
。这没关系,因为帖子必须从后端进行审核(即发布)。我现在需要的是在加载时设置YYYY-MM-DD
以设置select
上的选项。我并不是要求你们改变答案,我相信我能解决这个问题(尽管如果您能帮助解决这个新问题,我们将不胜感激)。
I have three variables set, $date_legible
(in the format of F jS, Y
, i.e. January 1st, 2011), $date_timestamp
(self-explanatory), and $date_normal
(in the format of YYYY-MM-DD)
I have three select fields:
<select name="date_mo">
<option value="01">January</option>
<option value="02">February</option>
<option value="03">March</option>
<option value="04">April</option>
<option value="05">May</option>
<option value="06">June</option>
<option value="07">July</option>
<option value="08">August</option>
<option value="09">September</option>
<option value="10">October</option>
<option value="11">November</option>
<option value="12">December</option>
</select>
<select name="date_dy">
<option value="01">1</option>
<option value="02">2</option>
<option value="03">3</option>
<option value="04">4</option>
<option value="05">5</option>
<option value="06">6</option>
<option value="07">7</option>
<option value="08">8</option>
<option value="09">9</option>
<option value="10">10</option>
<option value="11">11</option>
<option value="12">12</option>
<option value="13">13</option>
<option value="14">14</option>
<option value="15">15</option>
<option value="16">16</option>
<option value="17">17</option>
<option value="18">18</option>
<option value="19">19</option>
<option value="20">20</option>
<option value="21">21</option>
<option value="22">22</option>
<option value="23">23</option>
<option value="24">24</option>
<option value="25">25</option>
<option value="26">26</option>
<option value="27">27</option>
<option value="28">28</option>
<option value="29">29</option>
<option value="30">30</option>
<option value="31">31</option>
</select>
<select name="date_yr">
<?php for($year=$curryear;$year<$curryear+51;$year++){ ?>
<option value="<?php echo $year; ?>"><?php echo $year; ?></option>
<?php } ?>
</select>
I know I want to convert the timestamp, but I will ultimately need to explode the output for the $month
, $day
, and $year
. The problem is I don't know how to check the selects to the values and automatically select the correct option.
Can anyone help? Thanks!
UPDATE
I now have one more variable, because I'm having users submit from the front end, and Gravity Forms submits as YYYY-MM-DD
.
Prior to diving into the solutions already posted (thank you guys [and gals] by the way), here's a little more information:
I'm running WordPress and have three custom fields as described above. When a user submits a post from the front end, the only custom field that's filled out is $date_normal
. This is okay, because a post has to be moderated (i.e. published) from the backend. What I NOW need is on load to set the YYYY-MM-DD
to set the options on the select
. I'm not asking you guys to alter your answers, I'm sure I can figure it out (though if you can help with this new problem, it would be greatly appreciated).
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如果我正确理解您的问题,那么您有一个时间戳,并且在渲染页面时需要使用时间戳来选择适当的选择选项。
作为预警 - 这将使得选择无效日期成为可能,例如 2 月 31 日(不存在)。当月份更改时,您可能需要考虑使用 JavaScript 重新绘制年份下拉菜单。由于您没有指定任何 javascript 库(并且不清楚无效日期的可能性有多重要),因此我不会冒险展示其代码,但这不会非常困难。
输出:
编辑
如果您的源数据采用
YYYY-MM-DD
格式。为了将其转换为时间戳,从而使用我发布的示例代码,请对该格式化日期值调用strtotime
。因此,上面代码中唯一需要更改的行是 $timestamp = strtotime($the_formatted_date);If I understand your question correctly, you have a timestamp and you need to use the timestamp to select the appropriate select options when you render the page.
As a forewarning - this will make it possible to select invalid dates, for example February 31st (does not exist). You may want to consider re-drawing the year drop-down when the month is changed using javascript. Since you didn't specify any javascript library (and it is not clear how important the possibility of an invalid date is), I will not venture to show code for that, but it would not be terribly difficult.
Output:
EDIT
If your source data will be in the format of
YYYY-MM-DD
. In order to translate that into a timestamp, and thus work with the example code I've posted, is to callstrtotime
on that formatted date value. Thus, the only line in the code above that would need to be changed is$timestamp = strtotime($the_formatted_date);
我个人会将这 3 个字段转换为更用户友好的日期选择器(例如使用 jQuery UI) ,但要在打开页面时选择正确的选项,您需要为每个选项添加复选标记。
年份示例:
I would personally convert the 3 fields to a more user-friendly date selector (using for example jQuery UI), but to have the correct option selected when you open the page, you need to add a check to each option.
Example for the year: