确定新的购物车条目是否包含与购物车/会话中已有条目相同的标识符

Question

我有一个功能可以在购物车中添加定制的浮雕。购物车存储在会话变量中。如果客户决定构建完全相同的客串，我不想在数组中添加另一个条目，我只想能够在所述产品的数量上再添加 1 个条目。问题是，当脚本到达检查数组中是否存在值时，它会返回 false 并向数组添加一个新条目。我对 PHP 相当陌生，所以我不确定我是否以正确的方式处理它。

function AddToCart($subpid,$subtype,$subprice,$subtotal,$subcarving,$subline1,$subline2){
    global $form;
    
    $exist = false;
    $i=0;
    
    if(!isset($_SESSION['cart'])){
        $_SESSION['cart'] = array(0 => array("Product ID" => $subpid, "Type" => $subtype, "Price" => "$".$subprice, "Subtotal" => "$".$subtotal, "Carving" => $subcarving, "Line 1" => $subline1, "Line 2" => $subline2, "Quantity" => 1));
    }
    else{
        foreach($_SESSION['cart'] as $item){
            $i++;
            while(list($key,$value) = each($item)){
                /* If product exist add 1 to quantity */
                if($key == "Product ID" && $value == $subpid && $key == "Type" && $value == $subtype && $key == "Price" && $value == "$".$subprice && $key == "Subtotal" && $value == "$".$subtotal  && $key == "Carving" && $value == $subcarving && $key == "Line 1" && $value == $subline1 && $key == "Line 2" && $value == $subline2){
                    array_splice($_SESSION['cart'], $i-1, 1, array(array("Product ID" => $subpid, "Type" => $subtype, "Price" => "$".$subprice, "Subtotal" => "$".$subtotal, "Carving" => $subcarving, "Line 1" => $subline1, "Line 2" => $subline2, "Quantity" => $item['Quantity'] + 1)));
                    $exist = true;
                }
            }
        }
        if($exist == false){
            array_push($_SESSION['cart'], array("Product ID" => $subpid, "Type" => $subtype, "Price" => "$".$subprice, "Subtotal" => "$".$subtotal, "Carving" => $subcarving, "Line 1" => $subline1, "Line 2" => $subline2, "Quantity" => 1));
        }
    }
    return 0;
}

如果我只是使用： $key == "Product ID" && $value == $subid 它将返回 true 并更新数量，但问题是如果客户购买两个具有相同 id 但雕刻不同的浮雕或雕刻，我的购物车将会关闭。

Answer 1

我认为你让这种方式变得比它必须的更加令人困惑......

我会像这样设置你的购物车数组：

$cart[0]["name"] = "whatever";
$cart[0]["ProductID"] = "1234";
$cart[0]["price"] = 0.00;
$cart[0]["quantity"] = 1;
$cart[0]["options"] = array(
     "subcarving" => "asdf",
     "subline1"   => "asdfsafd",
     "subline2"   => "asfdsadfdf");

然后你可以像这样通过简单的循环来处理它：

$didadd = 0;
for($x = 0; $x < sizeof($cart); $x++) {
    if($subid == $cart[$x]["ProductID"]) {
        // check options
        $sameOpts = 1;
        foreach($cart[$x]["options"] as $key => $val) {

            if($val != ${$key}) { // checks if the current items option[val] = function(val)
                $sameOpts = 0;
            }

        }

        if($sameOpts) {
            $didadd = 1; // sets the flag that we added the element.
            // increase quantity since the product id and options matched.

        } else {
            $didadd = 1;
            // add new element
            // sets the flag that we added the element
        }

    }
} 

if(!$didadd) { 
    // still need to add the item
    // do code to create new $cart item here.

}

Answer 2

它不起作用，因为您同时与 && 语句比较每个键，但一次循环遍历每个键。取出 while 循环并像这样比较它：

if( $item['Product ID'] == $subpid ... //etc ) {

}

此外，您不需要 array_splice 只需更新项目即可。