按 UIButton 会导致无法识别的选择器错误

发布于 2024-12-02 22:42:02 字数 855 浏览 2 评论 0原文

我的 UIView 中有一个按钮，其创建方式如下：

UIBarButtonItem *editButton = 
        [[UIBarButtonItem alloc] initWithBarButtonSystemItem:UIBarButtonSystemItemEdit 
                                                      target:self       
                                                      action:@selector(toggleEdit)];
self.navigationItem.rightBarButtonItem = editButton;
[editButton release];

这是操作方法：

-(void) toggleEdit:(id)sender
{
}

但我收到此错误

2011-09-02 15:27:13.362 blubb[15006:207] -[DatabaseSelectionViewControllertoggleEdit]：无法识别的选择器发送到实例 0x5a29d80 2011-09-02 15:27:13.365 blubb[15006:207] * 由于未捕获的异常“NSInvalidArgumentException”而终止应用程序，原因：“-[DatabaseSelectionViewControllertoggleEdit]：无法识别的选择器发送到实例 0x5a29d80”

为什么会发生这种情况？

原文

I have a button in my UIView that is created like so:

UIBarButtonItem *editButton = 
        [[UIBarButtonItem alloc] initWithBarButtonSystemItem:UIBarButtonSystemItemEdit 
                                                      target:self       
                                                      action:@selector(toggleEdit)];
self.navigationItem.rightBarButtonItem = editButton;
[editButton release];

And this is the action method:

-(void) toggleEdit:(id)sender
{
}

but I get this error

2011-09-02 15:27:13.362 blubb[15006:207] -[DatabaseSelectionViewController toggleEdit]: unrecognized selector sent to instance 0x5a29d80
2011-09-02 15:27:13.365 blubb[15006:207] * Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[DatabaseSelectionViewController toggleEdit]: unrecognized selector sent to instance 0x5a29d80'

Why is this happening?

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傲世九天 2024-12-09 22:42:02

选择器的正确名称是

@selector(toggleEdit:)

没有 : 它会寻找具有此签名的方法：

-(void) toggleEdit  // No parameters
{
}

当您实际声明时：

-(void) toggleEdit:(id)sender
{
}

The correct name for your selector is

@selector(toggleEdit:)

Without the : it would look for a method with this signature:

-(void) toggleEdit  // No parameters
{
}

When you actually have declared:

-(void) toggleEdit:(id)sender
{
}

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心奴独伤 2024-12-09 22:42:02

更改

@selector(toggleEdit)

为

@selector(toggleEdit:)

Change

@selector(toggleEdit)

@selector(toggleEdit:)

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暮光沉寂 2024-12-09 22:42:02

对于其他遇到此问题的人，当您不再拥有某些东西并且该语句指向内存中的某个垃圾地址时，您也可能会收到“无法识别的选择器发送到实例 0x...”的错误。

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想你的星星会说话 2024-12-09 22:42:02

应该是：

-(IBAction) toggleEdit:(id)sender {}

和

@selector(toggleEdit:)

should be:

-(IBAction) toggleEdit:(id)sender {}

and

@selector(toggleEdit:)

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倥絔 2024-12-09 22:42:02

尝试：

UIBarButtonItem *editButton = [[UIBarButtonItem alloc]
initWithBarButtonSystemItem:UIBarButtonSystemItemEdit
target:self action:@selector(toggleEdit) forControlEvents:UIControlEventTouchUpInside];

Try:

UIBarButtonItem *editButton = [[UIBarButtonItem alloc]
initWithBarButtonSystemItem:UIBarButtonSystemItemEdit
target:self action:@selector(toggleEdit) forControlEvents:UIControlEventTouchUpInside];

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樱＆纷飞 2024-12-09 22:42:02

您尝试使用的方法需要一个参数，这意味着它的名称中有一个冒号 - 冒号实际上是名称的一部分。获取选择器时需要包含该冒号：

@selector(toggleEdit:)

请参阅消息语法部分：

选择器名称包含名称的所有部分，包括冒号，因此上例中的选择器名为 setOriginX:y:。它有两个冒号，因为它需要两个参数。但是，选择器名称不包含任何其他内容，例如返回类型或参数类型。

The method you're trying to use takes an argument, which means that it has a colon in its name -- the colon is actually part of the name. You need to include that colon when you get the selector:

@selector(toggleEdit:)

Refer to the Message Syntax section of The Objective-C Programming Language:

A selector name includes all the parts of the name, including the colons, so the selector in the preceding example is named setOriginX:y:. It has two colons, because it takes two parameters. The selector name does not, however, include anything else, such as return type or parameter types.

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