scanf 使用 %f 表示整数
我正在尝试解析一个由空格分隔的数字的字符串。但是，这些数字可以是整数或浮点数。 scanf 中有没有一种方法可以将整数和数字解析为一个集体浮点数？
例如：
float arg1, arg2 = 0;
sscanf("LINE 10 10", "LINE %f %f", &arg1, &arg2);
// and
sscanf("LINE 10.0 10.0", "LINE %f %f", &arg1, &arg2);
I am trying to parse a string that has some numbers seperated by a space. However, these numbers could be integers or floats. Is there a way in scanf to parse both integers and numbers as one collective float?
For example:
float arg1, arg2 = 0;
sscanf("LINE 10 10", "LINE %f %f", &arg1, &arg2);
// and
sscanf("LINE 10.0 10.0", "LINE %f %f", &arg1, &arg2);
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它只是有效的，整数是浮点数的特殊情况。
但请注意，大整数可能无法用浮点数精确表示（例如
1e9 + 1），但我认为您不必为此担心。It just works, integers are special cases of floating points.
Note, however, that large integers might not be able to be represented precisely by floats (eg.
1e9 + 1), but I don't think you bother about that.事实证明我的测试是错误的，你可以用 %f 读取整数。
Turns out my tests were wrong, you can read from an integer with %f.