组合两个时间间隔查询

Question

我有一个名为 Call_Data 的表，数据如下所示：

Arr_Date                   Interval    Han_Time   SL_Time  
2011-03-16 18:39:31.000    1830        1200       245
2011-03-16 20:06:03.000    2000        261        85
2011-03-31 00:35:42.000    0030        1900       400
2011-03-31 02:13:06.000    0200        2000       350

现在我想知道 Han_time > 的记录数1800 和 SL_Time>300

所以我编写了两个查询来执行此操作：

  Select Arr_Date, Interval,
    Count(*) AS Han_Time_1800
    From Call_Data
    where Han_Time>1800
    Group by Arr_Date,Interval
    Order by Arr_Date,Interval

Select Arr_Date, Interval,
Count(*) AS SL_Time_300
From Call_Data
where SL_Time>300
Group by Arr_Date,Interval
Order by Arr_Date,Interval

是否有一种方法可以在一个查询中获取这两个值？

Answer 1

select Arr_Date,
       Interval,
       sum(case when Han_Time > 1800 then 1 else 0 end) as Han_Time_1800,
       sum(case when SL_Time > 300 then 1 else 0 end) as SL_Time_300
from Call_Data
where Han_Time > 1800 or 
      SL_Time > 300
group by Arr_Date, Interval
order by Arr_Date, Interval 

Answer 2

这不会有帮助吗：

Select Arr_Date, Interval,
    Count(*) AS Han_Time_1800
    From Call_Data
    where Han_Time>1800
    and SL_Time>300
    Group by Arr_Date,Interval
    Order by Arr_Date,Interval