密码分析：如何从使用相同密码进行异或加密的多个十六进制值中找到密码？
我非常不确定是否可以从多个使用相同密码进行异或加密的十六进制值中找到密码？
例如，这些是一些十六进制值，全部使用相同的十六进制密码进行异或加密，其长度与这些值完全相同：
a0c91eab4f88c644433311f88b733655c3d03148c25b375123545d8fb3fe7ec7
b885f3cb8f529670040f3e6b15afa84a1a85ace03b108d3b410bc17747352bc3
77d147fdf263471fdfb756c436c1b86911de0a1d688997cfcabc5f6d34a6e045
464c506a68b73f4004e553b215c41ca9ec45c1200c4072ee940596e6760c2007
860a2f619063990663d3fc15d149e6baec423f40d6dd6d5c714ae373cee05985
188c1720cacc341cda9642feecfb05d89af2fe0e5e4bf560f1b85eec6a5b99e8
c3c9271bcd0a295276f9fd1bca172c4be45d3bdfc437992cfdd4a6914d03bdfa
这里有人知道如何解决该问题吗？
@phs 和 @Kerrek SB
感谢您的回复。我真的很想为您的评论添加答案，但不幸的是我无法添加，因为评论链接在这个 JavaScript-Error 看起来不起作用。不知道那是怎么回事。
错误：
条件后缺少 )
源文件： http://cdn.sstatic.net/js/full.js? v=ea83ae356357
行：1，列：242
源代码：comment")>-1){var i=g.attr("id").substr("comments-link-".length);var h=c(i);b(i ,h,f);返回真}返回false};return{loadRest:d,init:a,jCommentsDiv:c,showComments:e,fetchComments:b}})();StackExchange.share=(function(){函数a(d,b,c){if (!1;''.concat(d, ...
密文是ASCII（0 ... 254）转换为十六进制，密码只是与密文长度相同的十六进制字符串。
@muntoo
非常感谢您对我的问题进行了正确的格式化。我真的很想知道你是如何做到的，因为我看不到你是如何做到的？这个网站的行为真的很奇怪，因为所有有用的信息而令人难过。点击任何其他消息后，我经常会注销，链接不起作用，按钮不起作用等等......
干杯， Karl-Uwe
P.S.：仍然无法对评论发表回复，只有编辑链接可以按预期工作:-(
好吧，因为这个网站无法正常工作，因为我的 NoScript- 和 Ghostery-AddOn 阻止了许多外国域的加载我现在放弃了这个网站的某种奇怪的 JavaScript
我正在寻找的密码是 。 26ffe258d67de61313fc50c55b6afe5f58cbf7bd446354e02947b6c803f13d04
我想不可能通过密码分析找到它，因为它是使用随机十六进制字符串进行异或加密。事实上，如果我每次使用随机字符串加密相同的文本，那么反之亦然。 - 没有机会破译它，
干杯，再见 。 卡尔-乌韦
I am pretty unsure if it might be possible to find the password out of several Hex-Values which are XOR encrypted all with the same password?
For example these are some HEX values all XOR encrypted with the same HEX password which has exactly the same length as these values:
a0c91eab4f88c644433311f88b733655c3d03148c25b375123545d8fb3fe7ec7
b885f3cb8f529670040f3e6b15afa84a1a85ace03b108d3b410bc17747352bc3
77d147fdf263471fdfb756c436c1b86911de0a1d688997cfcabc5f6d34a6e045
464c506a68b73f4004e553b215c41ca9ec45c1200c4072ee940596e6760c2007
860a2f619063990663d3fc15d149e6baec423f40d6dd6d5c714ae373cee05985
188c1720cacc341cda9642feecfb05d89af2fe0e5e4bf560f1b85eec6a5b99e8
c3c9271bcd0a295276f9fd1bca172c4be45d3bdfc437992cfdd4a6914d03bdfa
Has anyone around here an idea how to solve that problem?
@phs and @Kerrek SB
Thanks for your response. I would really like to add an answer to your comments but unfortunately I am unable because the comment link does not work as of this JavaScript-Error as it seems. Not sure what that is all about.
Error:
missing ) after condition
Source File: http://cdn.sstatic.net/js/full.js?v=ea83ae356357
Line: 1, Column: 242
Source Code:comment")>-1){var i=g.attr("id").substr("comments-link-".length);var h=c(i);b(i,h,f);return true}return false};return{loadRest:d,init:a,jCommentsDiv:c,showComments:e,fetchComments:b}})();StackExchange.share=(function(){function a(d,b,c){if(!1;''.concat(d, ...
The ciphertext is ASCII (0 ... 254) converted into hex, the password is just a hex string same length as the ciphertext.
@muntoo
Many thanks for the proper formatting of my question. I really would like to know how you managed that because I am not able to see how you did it? This website is really strange in its behaviour, which is quit sad because of all the useful information. I get constantly logged out after clicking on any other message, links don't work, buttons don't work and so on ...
Cheers,
Karl-Uwe
P.S.: Still unable to post a reply to a comment, only the edit link is working as expected :-(
Okay than as this website does not work properly because my NoScript- and Ghostery-AddOn preventing so many foreign domains from loading some kind of weird JavaScript for this website I give up now.
The password I was searching for is 26ffe258d67de61313fc50c55b6afe5f58cbf7bd446354e02947b6c803f13d04
I suppose it's impossible to find it through cryptanalysis because it's an XOR enciphering with random HEX strings. In fact if I would encipher the same text every time with a random string it would be the same the other way round - no chance to decipher it.
Cheers and bye,
Karl-Uwe
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