如何在具有多列的动物园对象中使用“apply.monthly”
我有一个名为 pp 的动物园对象,其中包含每日数据和 77 列,如下所示:
X02R X03N X04K X04N X04R X06I X06N X08J X08P X09O X11O X12L X14N X15G X16K (...)
1961-01-01 8.3 5.2 3.2 0.0 8.7 5.2 15.0 7.2 11.5 13.0 0.0 4.9 0.0 2.9 6.0
1961-01-02 1.1 3.2 10.0 0.0 0.0 3.5 0.0 8.7 0.4 1.2 0.0 0.4 0.0 3.2 0.2
1961-01-03 12.0 4.2 50.5 0.0 9.0 38.5 15.0 31.7 1.7 8.7 9.0 69.2 4.2 22.2 9.2
(...)
我想对每一列使用 apply.monthly
,所以最终我仍然有 77 列,但每月数据而不是每日数据。我试过 apply.monthly(pp, FUN=sum)
但结果是一个只有一列的动物园对象(我认为是添加所有列)。
我还尝试了一个循环:
for (i in 1:77) { mensal<-apply.monthly(pp[,i], FUN=sum) }
但它也只生成一列(第 77 列)。我也许可以通过一些试验和错误来使循环工作,但需要很长时间才能计算(我有 17897 行和 77 列),我想有一种更简单的方法可以在不使用循环的情况下完成此操作...所以如果你知道怎么办,请帮忙。谢谢!
I have a zoo object called pp with daily data and 77 columns that looks like this:
X02R X03N X04K X04N X04R X06I X06N X08J X08P X09O X11O X12L X14N X15G X16K (...)
1961-01-01 8.3 5.2 3.2 0.0 8.7 5.2 15.0 7.2 11.5 13.0 0.0 4.9 0.0 2.9 6.0
1961-01-02 1.1 3.2 10.0 0.0 0.0 3.5 0.0 8.7 0.4 1.2 0.0 0.4 0.0 3.2 0.2
1961-01-03 12.0 4.2 50.5 0.0 9.0 38.5 15.0 31.7 1.7 8.7 9.0 69.2 4.2 22.2 9.2
(...)
I want to use apply.monthly
to each of the columns, so in the end I will still have 77 columns but with monthly data instead of daily data. I triedapply.monthly(pp, FUN=sum)
but the result is a zoo object with just one column (I think is adding all the columns).
I also tried a loop:
for (i in 1:77)
but it also results in just one column (the 77th column). I might be able to make the loop work with some trial and error but it takes ages to compute ( I have 17897 rows and 77 columns) and I guess there is a simpler way of doing this without using loops... So if you know how, please help. Thanks!
{
mensal<-apply.monthly(pp[,i], FUN=sum)
}
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为了让
apply.monthly
返回具有多个列的对象,您必须使用按列操作的函数(或apply
不按列操作的函数) 。In order for
apply.monthly
to return an object with more than one column, you have to use a function that operates by column (orapply
a function that doesn't).试试这个:
Try this:
这只是一个可重现的示例。创建者:
但现在我有办法重新创建错误,也许我可以提供经过测试的解决方案:
看起来好像
sum
参数(最终)在位置上与apply.monthly
“FUN” 参数匹配,但是如果您命名,则会收到错误他们lapply 参数列表中都是“FUN”。This is just for a reproducible example. Created with:
But now that I have a way to re-create the error, maybe I can offer a tested solution:
It looks as though the
sum
argument (eventually) gets positionally matched to theapply.monthly
"FUN" argument, but you do get an error if you name them both "FUN" in the lapply argument list.