用于可变参数模板的基类列表
有没有办法访问 C++ 中某个类的所有基类？ 由于可变参数模板可用，我认为使用例如 ___BASE 是有意义的，它是当前类派生自的所有类型的可变参数列表。 这还可以检查类或其基类是否属于某种类型。 这已经可能了吗，还是我在这里遗漏了一些东西，为什么这是不可能的！？
Is there a way to access all base classes of a class in C++?
Since variadic templates are available I think it would make sense to have e.g. ___BASE which is a variadic list of all types the current class does derive from.
This would also enable a check whether a class or it's base classes are of a certain type.
Is this already possible or am I missing something here why this isn't possible!?
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尽管您可以自由地向类层次结构的所有成员添加合适的 typedef 以使此信息可用（例如 typedef 一个元组，其参数类型是祖先加上祖先的祖先）——你可能可以为此编写一个小混合。
至于检查某个东西是否是另一个东西的基础，这已经是 std::is_base_of 类型特征形式的标准的一部分。
There isn't a general mechanism in the language that'll tell you all the base classes, though you're free to add a suitable typedef to all members of your class hierarchy that will make this information available (e.g. typedef a tuple whose argument types are the ancestor plus the ancestor's ancestors) -- you could probably write a little mixin for that.
As for checking whether something is a base of another, that's already part of the standard in the shape of the
std::is_base_oftype trait.