Java中的Switch是循环的
我的 switch 语句一直循环。它应该打印您选择的选项，然后重新打印菜单。请帮忙！ 这是我的代码：
menu ="\n\t1 Create Account" +
"\n\t2 Check balance" +
"\n\t3 Withdraw" +
"\n\t1 Deposit" +
"\n\t2 Get account ID" +
"\n\t3 Set ID" +
"\n\t1 Display Account Info" +
"\n\t0 Quit\n\n\n";
System.out.println(menu);
System.out.println("\tEnter your selection: ");
option = scan.nextInt();
while (option != 0) {
switch (option) {
case 1: // Enter and Validate SSN
System.out.print("option 1");
break;
case 2: //Enter and Validate Passwords
System.out.print("option 2");
break;
case 3: //Enter,Verify, and Translate a Phone keypad Number
System.out.print("option 3");
break;
case 4: // Enter and Validate SSN
System.out.print("option 4");
break;
case 5: //Enter and Validate Passwords
System.out.print("option 5");
break;
case 6: //Enter,Verify, and Translate a Phone keypad Number
System.out.print("option 6");
break;
case 7: //Enter,Verify, and Translate a Phone keypad Number
System.out.print("option 7");
break;
default: outputString = "\nInvalid Selection\n";
System.out.println(outputString);
break;
}
}
My switch statement just keeps looping. It should print the option you choose and then reprint the menu. Please help!
Here is my code:
menu ="\n\t1 Create Account" +
"\n\t2 Check balance" +
"\n\t3 Withdraw" +
"\n\t1 Deposit" +
"\n\t2 Get account ID" +
"\n\t3 Set ID" +
"\n\t1 Display Account Info" +
"\n\t0 Quit\n\n\n";
System.out.println(menu);
System.out.println("\tEnter your selection: ");
option = scan.nextInt();
while (option != 0) {
switch (option) {
case 1: // Enter and Validate SSN
System.out.print("option 1");
break;
case 2: //Enter and Validate Passwords
System.out.print("option 2");
break;
case 3: //Enter,Verify, and Translate a Phone keypad Number
System.out.print("option 3");
break;
case 4: // Enter and Validate SSN
System.out.print("option 4");
break;
case 5: //Enter and Validate Passwords
System.out.print("option 5");
break;
case 6: //Enter,Verify, and Translate a Phone keypad Number
System.out.print("option 6");
break;
case 7: //Enter,Verify, and Translate a Phone keypad Number
System.out.print("option 7");
break;
default: outputString = "\nInvalid Selection\n";
System.out.println(outputString);
break;
}
}
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评论（4）
我很确定是您的
while循环正在执行循环。而且您永远不会更改循环体内option的值，因此它当然会连续运行。据推测，您想要将行： 移动
到循环的第一行：
I'm pretty sure it's your
whileloop that is doing the looping. And you are never changing the value ofoptionwithin the body of the loop, so of course it runs continuously.Presumably, you want to move the line:
To the first line of the loop:
选项在 while 循环中永远不会改变——如果您输入任何非
0的内容，则会导致无限循环Option is never changing in the while loop you have -- resulting in an endless loop if you type in anything that's not
0do while 循环需要更少的代码：
A do while loop would require less code:
您的代码会继续循环，因为当您处于循环中时
option的值永远不会改变。您需要以不同的方式编写逻辑。顺便说一句，switch不循环，while进行循环。Your code keeps on looping because value of
optionnever changes when you are in the loop. You need to write your logic differently. Btw,switchdoes not loop,whiledoes the looping.