C# 中的命令行参数

发布于 2024-12-02 07:36:58 字数 476 浏览 2 评论 0原文

再次大家好 Stackoverflow 社区，

今天我尝试在 C# 中使用命令行参数执行一个应用程序，这并不像我尝试

Process.Start(foldervar + "cocacola.exe", "pepsi.txt");

Cocacola.exe 写入并登录其当前文件夹那样困难。在我的命令行中，我像这样手动编写它，

C:\myfolder>cocacola.exe pepsi.txt

效果很好，但如果我在 C# 中尝试，则完全失败。

我读到 C# 将命令解析为 C:\myfolder>cocacola pepsi.txt，没有“.EXE”结尾。而且我手动测试了一下没有结局，这行不通。

现在，我的问题是让 C# 执行它的正确方法是什么 C:\myfolder>cocacola.exe pepsi.txt 带有“.EXE”

原文

Hello again Stackoverflow community,

Today I am trying to execute an application with commandline parameters in C#, that not realy difficult like I tried

Process.Start(foldervar + "cocacola.exe", "pepsi.txt");

Cocacola.exe writes and Log in its current folder. In my commandline I write it manually like this

C:\myfolder>cocacola.exe pepsi.txt

Works wonderful but if I try it in C# a total fail.

I read that C# parses the command as C:\myfolder>cocacola pepsi.txt, without the ".EXE" ending. And I tested it manually without the ending, and this does not work.

Now, my question is what is the correct way to get C# executing it C:\myfolder>cocacola.exe pepsi.txt with the ".EXE"

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遮云壑 2024-12-09 07:36:58

使用 ProcessStartInfo

http://www.dotnetperls.com/process-start

示例：

    System.Diagnostics.Process proc = new System.Diagnostics.Process();
    proc.WorkingDirectory=@"c:\someplace";
    proc.StartInfo.FileName="cocacola.exe";
    proc.StartInfo.Arguments="pepsi.txt";
    proc.Start();
    proc.WaitForExit();

这里是文档StartInfo 属性：

http://msdn.microsoft.com/en-us/library/system.diagnostics.processstartinfo.aspx

use ProcessStartInfo

http://www.dotnetperls.com/process-start

example:

    System.Diagnostics.Process proc = new System.Diagnostics.Process();
    proc.WorkingDirectory=@"c:\someplace";
    proc.StartInfo.FileName="cocacola.exe";
    proc.StartInfo.Arguments="pepsi.txt";
    proc.Start();
    proc.WaitForExit();

here is docs on the StartInfo properties:

http://msdn.microsoft.com/en-us/library/system.diagnostics.processstartinfo.aspx

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陌路黄昏 2024-12-09 07:36:58

尝试设置 StartInfo 属性。

Process process = new Process();
process.StartInfo.FileName = @"C:\myfolder\cocacola.exe";
process.StartInfo.Arguments = @"C:\myfolder\pepsi.txt";
process.Start();

Try setting the StartInfo properties.

Process process = new Process();
process.StartInfo.FileName = @"C:\myfolder\cocacola.exe";
process.StartInfo.Arguments = @"C:\myfolder\pepsi.txt";
process.Start();

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伊面 2024-12-09 07:36:58

ProcessStartInfo 具有 WorkingDirectory 属性，您应将其设置为 C:\myfolder

请参阅：http://msdn.microsoft.com/en-us/library/system.diagnostics.processstartinfo.workingdirectory.aspx

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通知家属抬走 2024-12-09 07:36:58

您需要先设置工作目录

string foldervar = @"C:\myfolder";
Process process = new Process();
process.StartInfo.WorkingDirectory = foldervar;
process.StartInfo.FileName = @"cocacola.exe";
process.StartInfo.Arguments = @"pepsi.txt";
process.Start();

设置工作目录相当于在运行程序之前cd进入正确的目录。这就是相对路径的相对路径。

You need to set the working directory first

string foldervar = @"C:\myfolder";
Process process = new Process();
process.StartInfo.WorkingDirectory = foldervar;
process.StartInfo.FileName = @"cocacola.exe";
process.StartInfo.Arguments = @"pepsi.txt";
process.Start();

Setting the WorkingDirectory is equivilent to cding into the proper directory before running programs. It's what relative paths are relative to.

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