groovy 中的 XmlSlurper 和 http.get

发布于 2024-12-02 07:11:07 字数 1082 浏览 0 评论 0原文

我首先使用http.get保存一个txt文件：

         http.get(path: path,
           contentType: TEXT,
           query: [id:dapId, instance:alias, format:'xml', file:portalFile]) {resp, reader ->

           println "response status: ${resp.statusLine}"  
         println 'Headers: -----------'  
       resp.headers.each { h ->     
            println " ${h.name} : ${h.value}"  
       }

       new File(outputFileName).withWriter{out -> out << reader}
        }

然后在XmlSlurper().parse中的outputFileName中使用新创建的文件，如下所示：

    def inputFile = new File(outputFileName)
      def domain = new XmlSlurper().parse(inputFile)

但是在执行new XmlSlurper().parse(inputFile)时出现错误：

Caught: org.xml.sax.SAXParseException: White spaces are required between publicId and systemId.

我注意到使用http.get 创建的文本文件outputFileName 似乎是一个HTML 文件而不是XML 文件。因此，我将应该包含的 XML 代码复制并粘贴到了 outputFileName 中，跳过了代码的第一部分，只运行了 XmlSlurper().parse() 位，结果成功了。

outputFileName 应该是一个 xml 文件吗？它有很多 HTML 标签。

提前致谢！：D

原文

I first save a txt file using http.get:

         http.get(path: path,
           contentType: TEXT,
           query: [id:dapId, instance:alias, format:'xml', file:portalFile]) {resp, reader ->

           println "response status: ${resp.statusLine}"  
         println 'Headers: -----------'  
       resp.headers.each { h ->     
            println " ${h.name} : ${h.value}"  
       }

       new File(outputFileName).withWriter{out -> out << reader}
        }

And then use the newly created file in outputFileName in XmlSlurper().parse, as below:

    def inputFile = new File(outputFileName)
      def domain = new XmlSlurper().parse(inputFile)

But I get an error when doing new XmlSlurper().parse(inputFile):

Caught: org.xml.sax.SAXParseException: White spaces are required between publicId and systemId.

I noticed that the textfile outputFileName which is being created with http.get seems to be an HTML file and not an XML file. So I copied and pasted the XML code which it is supposed to contain into outputFileName, skipped the first part of the code and only ran the XmlSlurper().parse() bit and it worked.

Is outputFileName supposed to be an xml file? It has lots of HTML tags.

Thanks in advance! :D

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