遍历列表的Python列表并创建一个新列表
基本上，我有一个以下形式的字典：
'the trip':('The Trip','www.SearchHero.com',"See sponsored listings for 'The Trip.' Click here!",0.1,'The Trip','3809466'),
'post office':('Post Office','www.SearchHero.com',"See sponsored listings for 'Post Office.' Click here!",0.1,'Post Office','5803938'),
'balanced diets':('Last Minute Deals','www.SearchHero.com',"See sponsored listings for 'Last Minute Deals.' Click here!",0.1,'Last Minute Deals','1118375')
我想输出以下形式的列表：
{'.1, 3809466', '.1, 5803938', '.1, '1118375'}
我是 Python 新手，但在 Ruby 中我知道我会使用 map 函数。 python 中的等价物是什么？提前致谢
Basically, I have a dictionary of the form:
'the trip':('The Trip','www.SearchHero.com',"See sponsored listings for 'The Trip.' Click here!",0.1,'The Trip','3809466'),
'post office':('Post Office','www.SearchHero.com',"See sponsored listings for 'Post Office.' Click here!",0.1,'Post Office','5803938'),
'balanced diets':('Last Minute Deals','www.SearchHero.com',"See sponsored listings for 'Last Minute Deals.' Click here!",0.1,'Last Minute Deals','1118375')
I want to output a list of the form:
{'.1, 3809466', '.1, 5803938', '.1, '1118375'}
I am new to Python, but in Ruby I know I'd use the map function. What is the equivalent in python? Thanks in advance
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一个基本示例：
您可以调整格式字符串以更好地控制输出。
底层语法构造称为列表理解
A basic example:
you can adapt the format string to have more control over the output.
The underlying syntax construct is called a list comprehension