如何从另一个数组值中过滤数组值并返回新数组？
我有两个数组：$all_languages 和 $taken_languages。第一个包含所有语言（例如 200 种或其他语言），第二个包含之前选择的语言（从 0 到 200 种）。
我需要从 $all_languages 中删除已采用的所有语言 ($taken_languages) 并返回新数组 - $available_languages。
我的解决方案是两个循环，但是，首先，它不能按预期工作，其次 - 它“不酷”，我相信有更好的解决方案！你能指出我正确的道路吗？
这是我以前做过的，但是，正如我所说，它没有按预期工作......
if (!empty($taken_languages)) {
foreach ($all_languages as $language) {
foreach ($taken_languages as $taken_language) {
if ($taken_language != $language) {
$available_languages[] = $language;
break;
}
}
}
} else {
$available_languages = $all_languages;
}
感谢您的建议！
I have two arrays: $all_languages and $taken_languages. One contains all languages (like 200 or something), but second - languages that have been chosen before (from 0 to 200).
I need to remove all languages that have been taken ($taken_languages) from $all_languages and return new array - $available_languages.
My solution was two loops, but, first, it doesn't work as expected, second - it's 'not cool' and I believe that there are better solutions! Can you point me to the correct path?
This is what I have done before, but, as I said, it doesn't work as expected...
if (!empty($taken_languages)) {
foreach ($all_languages as $language) {
foreach ($taken_languages as $taken_language) {
if ($taken_language != $language) {
$available_languages[] = $language;
break;
}
}
}
} else {
$available_languages = $all_languages;
}
Thanks in advice!
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PHP 为此有一个内置函数（以及几乎所有其他内容：P）
PHP 手册 (array_diff)
PHP has a built in function for this (and just about everything else :P)
PHP Manual (array_diff)
array_diff函数将适合您。http://php.net/manual/en/function.array-diff.php
The
array_difffunction will work for you.http://php.net/manual/en/function.array-diff.php