如何匹配以“H”开头的 10 个字符的子字符串用 Ruby 写成更长的字符串？

发布于 2024-12-02 01:33:14 字数 265 浏览 0 评论 0原文

我有以下字符串：

/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml

在 Ruby 中，如何提取以字母 H 开头且在 H 之后包含 9 个数字（仅数字）的前 10 个字符子字符串。在上面的示例中，子字符串将为 H200000787

原文

I have the following string:

/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml

In Ruby, how do I extract the first 10 character substring that starts with the letter H and contains 9 digits (digits only) after the H. In this above example, the substring would be H200000787

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許願樹丅啲祈禱 2024-12-09 01:33:14

String#[] 方法是您所需要的：

str = '/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml'

puts str[/H\d{9}/]     #=> H200000787

String#[] method is what you need:

str = '/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml'

puts str[/H\d{9}/]     #=> H200000787

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极致的悲 2024-12-09 01:33:14

irb(main):001:0> s = "/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml"
=> "/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml"
irb(main):002:0> s =~ /H\d{9}/
=> 46
irb(main):003:0> amp;
=> "H200000787"

irb(main):001:0> s = "/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml"
=> "/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml"
irb(main):002:0> s =~ /H\d{9}/
=> 46
irb(main):003:0> amp;
=> "H200000787"

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~没有更多了~