如何将新变量与类中的默认变量进行匹配？

Question

在 jQuery 中有 $.extend() 函数。这基本上就像将默认设置与输入设置相匹配一样。好吧，我想在 PHP 中使用类似的技术，但似乎没有类似的功能。所以我想知道：是否有与 .extend() 类似的函数，但在 PHP 中？如果没有，还有什么替代方案？ >

这是一个示例类，以及我当前如何获得此效果。我还添加了一条评论，我希望如何做到这一点：

class TestClass {
    // These are the default settings:
    var $settings = array(
        'show' => 10,
        'phrase' => 'Miley rocks!',
        'by' => 'Kalle H. Väravas',
        'version' => '1.0'
    );
    function __construct ($input_settings) {
        // This is how I would wish to do this:
        // $this->settings = extend($this->settings, $input_settings);

        // This is what I want to get rid of:
        $this->settings['show'] = empty($input_settings['show']) ? $this->settings['show'] : $input_settings['show'];
        $this->settings['phrase'] = empty($input_settings['phrase']) ? $this->settings['phrase'] : $input_settings['phrase'];
        $this->settings['by'] = empty($input_settings['by']) ? $this->settings['by'] : $input_settings['by'];
        $this->settings['version'] = empty($input_settings['version']) ? $this->settings['version'] : $input_settings['version'];

        // Obviously I cannot do anything neat or dynamical with $input_settings['totally_new'] :/
    }
    function Display () {
        // For simplifying purposes, lets use Display and not print_r the settings from construct
        return $this->settings;
    }
}

$new_settings = array(
    'show' => 30,
    'by' => 'Your name',
    'totally_new' => 'setting'
);

$TC = new TestClass($new_settings);

echo '<pre>'; print_r($TC->Display()); echo '</pre>';

如果您注意到，有一个全新的设置：$new_settings['totally_new']。它应该作为 $this->settings['totally_new'] 包含在数组中。 PS：上面的代码输出 this。

Answer 1

尝试使用 array_merge php 函数。代码：

array_merge($this->settings, $input_settings);