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如何列出iOS中uiviewcontroller中的所有子视图？

发布于 2024-12-02 00:12:22 字数 110 浏览 1 评论 0原文

我想列出 UIViewController 中的所有子视图。我尝试了 self.view.subviews ，但并没有列出所有子视图，例如没有找到 UITableViewCell 中的子视图。有什么想法吗？

原文

I want to list out all the subviews in a UIViewController. I tried self.view.subviews, but not all of the subviews are listed out, for instance, the subviews in the UITableViewCell are not found. Any idea?

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评论（22）

寄居者 2024-12-09 00:12:22

您必须递归迭代子视图。

- (void)listSubviewsOfView:(UIView *)view {
    
    // Get the subviews of the view
    NSArray *subviews = [view subviews];

    for (UIView *subview in subviews) {
        
        // Do what you want to do with the subview
        NSLog(@"%@", subview);

        // List the subviews of subview
        [self listSubviewsOfView:subview];
    }
}

You have to recursively iterate the sub views.

- (void)listSubviewsOfView:(UIView *)view {
    
    // Get the subviews of the view
    NSArray *subviews = [view subviews];

    for (UIView *subview in subviews) {
        
        // Do what you want to do with the subview
        NSLog(@"%@", subview);

        // List the subviews of subview
        [self listSubviewsOfView:subview];
    }
}
回复 原文
内心旳酸楚 2024-12-09 00:12:22

xcode/gdb 转储视图层次结构的内置方法很有用——recursiveDescription，根据 http://developer.apple.com/library/ios/#technotes/tn2239/_index.html

它输出一个更完整的视图层次结构，您可能会发现它有用：

> po [_myToolbar recursiveDescription]

<UIToolbarButton: 0xd866040; frame = (152 0; 15 44); opaque = NO; layer = <CALayer: 0xd864230>>
   | <UISwappableImageView: 0xd8660f0; frame = (0 0; 0 0); opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0xd86a160>>

The xcode/gdb built-in way to dump the view hierarchy is useful -- recursiveDescription, per http://developer.apple.com/library/ios/#technotes/tn2239/_index.html

It outputs a more complete view hierarchy which you might find useful:

> po [_myToolbar recursiveDescription]

<UIToolbarButton: 0xd866040; frame = (152 0; 15 44); opaque = NO; layer = <CALayer: 0xd864230>>
   | <UISwappableImageView: 0xd8660f0; frame = (0 0; 0 0); opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0xd86a160>>
回复 原文
带刺的爱情 2024-12-09 00:12:22

Swift 中优雅的递归解决方案：

extension UIView {

    func subviewsRecursive() -> [UIView] {
        return subviews + subviews.flatMap { $0.subviewsRecursive() }
    }

}

您可以在任何 UIView 上调用 subviewsRecursive() ：

let allSubviews = self.view.subviewsRecursive()

Elegant recursive solution in Swift:

extension UIView {

    func subviewsRecursive() -> [UIView] {
        return subviews + subviews.flatMap { $0.subviewsRecursive() }
    }

}

You can call subviewsRecursive() on any UIView:

let allSubviews = self.view.subviewsRecursive()
回复 原文
万人眼中万个我 2024-12-09 00:12:22

您需要递归打印，此方法还根据视图的深度进行制表符

-(void) printAllChildrenOfView:(UIView*) node depth:(int) d
{
    //Tabs are just for formatting
    NSString *tabs = @"";
    for (int i = 0; i < d; i++)
    {
        tabs = [tabs stringByAppendingFormat:@"\t"];
    }

    NSLog(@"%@%@", tabs, node);

    d++; //Increment the depth
    for (UIView *child in node.subviews)
    {
        [self printAllChildrenOfView:child depth:d];
    }

}

You need to print recursively, this method also tabs based on the depth of the view

-(void) printAllChildrenOfView:(UIView*) node depth:(int) d
{
    //Tabs are just for formatting
    NSString *tabs = @"";
    for (int i = 0; i < d; i++)
    {
        tabs = [tabs stringByAppendingFormat:@"\t"];
    }

    NSLog(@"%@%@", tabs, node);

    d++; //Increment the depth
    for (UIView *child in node.subviews)
    {
        [self printAllChildrenOfView:child depth:d];
    }

}
回复 原文
随心而道 2024-12-09 00:12:22

这是快速版本

 func listSubviewsOfView(view:UIView){

    // Get the subviews of the view
    var subviews = view.subviews

    // Return if there are no subviews
    if subviews.count == 0 {
        return
    }

    for subview : AnyObject in subviews{

        // Do what you want to do with the subview
        println(subview)

        // List the subviews of subview
        listSubviewsOfView(subview as UIView)
    }
}

Here is the swift version

 func listSubviewsOfView(view:UIView){

    // Get the subviews of the view
    var subviews = view.subviews

    // Return if there are no subviews
    if subviews.count == 0 {
        return
    }

    for subview : AnyObject in subviews{

        // Do what you want to do with the subview
        println(subview)

        // List the subviews of subview
        listSubviewsOfView(subview as UIView)
    }
}
回复 原文
明媚殇 2024-12-09 00:12:22

详细信息

  • Xcode 9.0.1、Swift 4
  • Xcode 10.2 (10E125)、Swift 5

解决方案

extension UIView {
    private func subviews(parentView: UIView, level: Int = 0, printSubviews: Bool = false) -> [UIView] {
        var result = [UIView]()
        if level == 0 && printSubviews {
            result.append(parentView)
            print("\(parentView.viewInfo)")
        }

        for subview in parentView.subviews {
            if printSubviews { print("\(String(repeating: "-", count: level))\(subview.viewInfo)") }
            result.append(subview)
            if subview.subviews.isEmpty { continue }
            result += subviews(parentView: subview, level: level+1, printSubviews: printSubviews)
        }
        return result
    }
    private var viewInfo: String { return "\(classForCoder), frame: \(frame))" }
    var allSubviews: [UIView] { return subviews(parentView: self) }
    func printSubviews() { _ = subviews(parentView: self, printSubviews: true) }
}

使用

 view.printSubviews()
 print("\(view.allSubviews.count)")

结果

在此处输入图像描述

Details

  • Xcode 9.0.1, Swift 4
  • Xcode 10.2 (10E125), Swift 5

Solution

extension UIView {
    private func subviews(parentView: UIView, level: Int = 0, printSubviews: Bool = false) -> [UIView] {
        var result = [UIView]()
        if level == 0 && printSubviews {
            result.append(parentView)
            print("\(parentView.viewInfo)")
        }

        for subview in parentView.subviews {
            if printSubviews { print("\(String(repeating: "-", count: level))\(subview.viewInfo)") }
            result.append(subview)
            if subview.subviews.isEmpty { continue }
            result += subviews(parentView: subview, level: level+1, printSubviews: printSubviews)
        }
        return result
    }
    private var viewInfo: String { return "\(classForCoder), frame: \(frame))" }
    var allSubviews: [UIView] { return subviews(parentView: self) }
    func printSubviews() { _ = subviews(parentView: self, printSubviews: true) }
}

Usage

 view.printSubviews()
 print("\(view.allSubviews.count)")

Result

enter image description here

回复 原文
靑春怀旧 2024-12-09 00:12:22

我参加聚会有点晚了，但有一个更通用的解决方案：

@implementation UIView (childViews)

- (NSArray*) allSubviews {
    __block NSArray* allSubviews = [NSArray arrayWithObject:self];

    [self.subviews enumerateObjectsUsingBlock:^( UIView* view, NSUInteger idx, BOOL*stop) {
        allSubviews = [allSubviews arrayByAddingObjectsFromArray:[view allSubviews]];
                   }];
        return allSubviews;
    }

@end

I'm a bit late to the party, but a bit more general solution:

@implementation UIView (childViews)

- (NSArray*) allSubviews {
    __block NSArray* allSubviews = [NSArray arrayWithObject:self];

    [self.subviews enumerateObjectsUsingBlock:^( UIView* view, NSUInteger idx, BOOL*stop) {
        allSubviews = [allSubviews arrayByAddingObjectsFromArray:[view allSubviews]];
                   }];
        return allSubviews;
    }

@end
回复 原文
甲如呢乙后呢 2024-12-09 00:12:22

如果您想要的只是一组 UIView，这是一个单行解决方案 (Swift 4+)：

extension UIView {
  var allSubviews: [UIView] {
    return self.subviews.reduce([UIView]()) { $0 + [$1] + $1.allSubviews }
  }
}

If all you want is an array of UIViews, this is a one liner solution (Swift 4+):

extension UIView {
  var allSubviews: [UIView] {
    return self.subviews.reduce([UIView]()) { $0 + [$1] + $1.allSubviews }
  }
}
回复 原文
压抑⊿情绪 2024-12-09 00:12:22

我使用这种方式：

NSLog(@"%@", [self.view subviews]);

在 UIViewController 中。

I use this way:

NSLog(@"%@", [self.view subviews]);

in the UIViewController.

回复 原文
深陷 2024-12-09 00:12:22

以我的方式，UIView的类别或扩展比其他的好得多
而递归是让所有子视图了解更多信息的关键点

：

https://github.com/ZhipingYang/XYDebugView

在此处输入图像描述

Objective-C

@implementation UIView (Recurrence)

- (NSArray<UIView *> *)recurrenceAllSubviews
{
    NSMutableArray <UIView *> *all = @[].mutableCopy;
    void (^getSubViewsBlock)(UIView *current) = ^(UIView *current){
        [all addObject:current];
        for (UIView *sub in current.subviews) {
            [all addObjectsFromArray:[sub recurrenceAllSubviews]];
        }
    };
    getSubViewsBlock(self);
    return [NSArray arrayWithArray:all];
}
@end

示例

NSArray *views = [viewController.view recurrenceAllSubviews];

Swift 3.1

extension UIView {
    func recurrenceAllSubviews() -> [UIView] {
        var all = [UIView]()
        func getSubview(view: UIView) {
            all.append(view)
            guard view.subviews.count>0 else { return }
            view.subviews.forEach{ getSubview(view: $0) }
        }
        getSubview(view: self)
        return all
    }
}

示例

let views = viewController.view.recurrenceAllSubviews()

直接使用sequence函数获取所有子视图

let viewSequence = sequence(state: [viewController.view]) { (state: inout [UIView] ) -> [UIView]? in
    guard state.count > 0 else { return nil }
    defer {
        state = state.map{ $0.subviews }.flatMap{ $0 }
    }
    return state
}
let views = viewSequence.flatMap{ $0 }

In my way, UIView's category or extension is much better than others
and recursive is the key point to get all subviews

learn more:

https://github.com/ZhipingYang/XYDebugView

enter image description here

Objective-C

@implementation UIView (Recurrence)

- (NSArray<UIView *> *)recurrenceAllSubviews
{
    NSMutableArray <UIView *> *all = @[].mutableCopy;
    void (^getSubViewsBlock)(UIView *current) = ^(UIView *current){
        [all addObject:current];
        for (UIView *sub in current.subviews) {
            [all addObjectsFromArray:[sub recurrenceAllSubviews]];
        }
    };
    getSubViewsBlock(self);
    return [NSArray arrayWithArray:all];
}
@end

example

NSArray *views = [viewController.view recurrenceAllSubviews];

Swift 3.1

extension UIView {
    func recurrenceAllSubviews() -> [UIView] {
        var all = [UIView]()
        func getSubview(view: UIView) {
            all.append(view)
            guard view.subviews.count>0 else { return }
            view.subviews.forEach{ getSubview(view: $0) }
        }
        getSubview(view: self)
        return all
    }
}

example

let views = viewController.view.recurrenceAllSubviews()

directly, use sequence function to get all subviews

let viewSequence = sequence(state: [viewController.view]) { (state: inout [UIView] ) -> [UIView]? in
    guard state.count > 0 else { return nil }
    defer {
        state = state.map{ $0.subviews }.flatMap{ $0 }
    }
    return state
}
let views = viewSequence.flatMap{ $0 }
回复 原文
上课铃就是安魂曲 2024-12-09 00:12:22

简单的 Swift 示例：

 var arrOfSub = self.view.subviews
 print("Number of Subviews: \(arrOfSub.count)")
 for item in arrOfSub {
    print(item)
 }

Simple Swift example:

 var arrOfSub = self.view.subviews
 print("Number of Subviews: \(arrOfSub.count)")
 for item in arrOfSub {
    print(item)
 }
回复 原文
毁我热情 2024-12-09 00:12:22

UITableViewCell 中的子视图未打印的原因是您必须输出顶层的所有子视图。单元格的子视图不是视图的直接子视图。

为了获取 UITableViewCell 的子视图，您需要在打印循环中确定哪些子视图属于 UITableViewCell （使用 isKindOfClass:），然后循环遍历其子视图

编辑：这篇关于 简单的 UIView 调试 可能会有所帮助

The reason the subviews in a UITableViewCell are not printed is because you must be outputting all the subviews in the top level. The subviews of the cell are not the direct subviews of your view.

In order to get the UITableViewCell's subviews, you need to determine the which subviews belong to a UITableViewCell (using isKindOfClass:) in your print loop and then loop through it's subviews

Edit: This blog post on Easy UIView Debugging may potentially help

回复 原文
只有一腔孤勇 2024-12-09 00:12:22

我编写了一个类别来列出视图控制器持有的所有视图，其灵感来自之前发布的答案。

@interface UIView (ListSubviewHierarchy)
- (NSString *)listOfSubviews;
@end

@implementation UIView (ListSubviewHierarchy)
- (NSInteger)depth
{
    NSInteger depth = 0;
    if ([self superview]) {
        deepth = [[self superview] depth] + 1;
    }
    return depth;
}

- (NSString *)listOfSubviews
{
    NSString * indent = @"";
    NSInteger depth = [self depth];

    for (int counter = 0; counter < depth; counter ++) {
        indent = [indent stringByAppendingString:@"  "];
    }

    __block NSString * listOfSubviews = [NSString stringWithFormat:@"\n%@%@", indent, [self description];

    if ([self.subviews count] > 0) {
        [self.subviews enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
            UIView * subview = obj;
            listOfSubviews = [listOfSubviews stringByAppendingFormat:@"%@", [subview listOfSubviews]];
        }];
    }
    return listOfSubviews;
}
@end

要列出视图控制器持有的所有视图，只需 NSLog("%@",[self listOfSubviews])，其中 self 表示视图控制器本身。虽然它的效率并不高。

另外，您可以使用 NSLog(@"\n%@", [(id)self.view PerformSelector:@selector(recursiveDescription)]); 来做同样的事情，我认为它更多比我的实施效率高。

I wrote a category to list all views held by a view controller which inspired by the answers posted before.

@interface UIView (ListSubviewHierarchy)
- (NSString *)listOfSubviews;
@end

@implementation UIView (ListSubviewHierarchy)
- (NSInteger)depth
{
    NSInteger depth = 0;
    if ([self superview]) {
        deepth = [[self superview] depth] + 1;
    }
    return depth;
}

- (NSString *)listOfSubviews
{
    NSString * indent = @"";
    NSInteger depth = [self depth];

    for (int counter = 0; counter < depth; counter ++) {
        indent = [indent stringByAppendingString:@"  "];
    }

    __block NSString * listOfSubviews = [NSString stringWithFormat:@"\n%@%@", indent, [self description];

    if ([self.subviews count] > 0) {
        [self.subviews enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
            UIView * subview = obj;
            listOfSubviews = [listOfSubviews stringByAppendingFormat:@"%@", [subview listOfSubviews]];
        }];
    }
    return listOfSubviews;
}
@end

To list all views held by a view controller, just NSLog("%@",[self listOfSubviews]), which self means the view controller itself. Though it's not quit efficient.

Plus, you can use NSLog(@"\n%@", [(id)self.view performSelector:@selector(recursiveDescription)]); to do the same thing, and I think it's more efficient than my implementation.

回复 原文
野心澎湃 2024-12-09 00:12:22

您可以尝试一种奇特的数组技巧，例如：

[self.view.subviews makeObjectsPerformSelector: @selector(printAllChildrenOfView)];

只需一行代码。当然，您可能需要调整您的方法 printAllChildrenOfView 以不接受任何参数或创建新方法。

You could try a fancy array trick, like:

[self.view.subviews makeObjectsPerformSelector: @selector(printAllChildrenOfView)];

Just one line of code. Of course, you might need to adjust your method printAllChildrenOfView to not take any parameters or make a new method.

回复 原文
财迷小姐 2024-12-09 00:12:22

兼容 Swift 2.0

这里有一个递归方法来获取通用视图的所有子视图：

extension UIView {
  func subviewsList() -> [UIView] {
      var subviews = self.subviews
      if subviews.count == 0 {
          return subviews + []
      }
      for v in subviews {
         subviews += v.listSubviewsOfView()
      }
      return subviews
  }
}

所以你可以用这种方式在任何地方调用：

let view = FooController.view
let subviews = view.subviewsList()

Swift 2.0 compatible

Here a recursive method to obtains all subviews of a generic view:

extension UIView {
  func subviewsList() -> [UIView] {
      var subviews = self.subviews
      if subviews.count == 0 {
          return subviews + []
      }
      for v in subviews {
         subviews += v.listSubviewsOfView()
      }
      return subviews
  }
}

So you can call everywhere in this way:

let view = FooController.view
let subviews = view.subviewsList()
回复 原文
ゝ偶尔ゞ 2024-12-09 00:12:22

输入图片此处描述

最短解决方案

for subview in self.view.subviews {
    print(subview.dynamicType)
}

结果

UIView
UIView
UISlider
UISwitch
UITextField
_UILayoutGuide
_UILayoutGuide

注释

  • 如您所见，此方法不会递归列出子视图。请参阅其他一些答案。

enter image description here

Shortest solution

for subview in self.view.subviews {
    print(subview.dynamicType)
}

Result

UIView
UIView
UISlider
UISwitch
UITextField
_UILayoutGuide
_UILayoutGuide

Notes

  • As you can see, this method does not list the subviews recursively. See some of the other answers for that.
回复 原文
硪扪都還晓 2024-12-09 00:12:22

这是对这个答案的重写：

您必须首先获取指向要打印其所有子视图的对象的指针/引用。有时您可能会发现通过其子视图访问该对象更容易找到该对象。就像po someSubview.superview。这将为您提供如下信息：

Optional<UIView>
  ▿ some : <FacebookApp.WhatsNewView: 0x7f91747c71f0; frame = (30 50; 354 636); clipsToBounds = YES; layer = <CALayer: 0x6100002370e0>>
  • FaceBookApp 是您的应用程序名称
  • WhatsNewView 是您的超级视图的类型
  • 0x7f91747c71f0 是指向超级视图的指针。

要打印 superView，您必须使用断点。

现在要执行此步骤，您只需单击“查看调试层次结构”即可。不需要断点

在此处输入图像描述

然后你可以轻松地做到：

po [0x7f91747c71f0 recursiveDescription]

这对我来说返回了类似的内容：

<FacebookApp.WhatsNewView: 0x7f91747c71f0; frame = (30 50; 354 636); clipsToBounds = YES; layer = <CALayer: 0x6100002370e0>>
   | <UIStackView: 0x7f91747c75f0; frame = (45 60; 264 93); layer = <CATransformLayer: 0x610000230ec0>>
   |    | <UIImageView: 0x7f916ef38c30; frame = (10.6667 0; 243 58); opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0x61000003b840>>
   |    | <UIStackView: 0x7f91747c8230; frame = (44.6667 58; 174.667 35); layer = <CATransformLayer: 0x6100006278c0>>
   |    |    | <FacebookApp.CopyableUILabel: 0x7f91747a80b0; baseClass = UILabel; frame = (44 0; 86.6667 16); text = 'What's New'; gestureRecognizers = <NSArray: 0x610000c4a770>; layer = <_UILabelLayer: 0x610000085550>>
   |    |    | <FacebookApp.CopyableUILabel: 0x7f916ef396a0; baseClass = UILabel; frame = (0 21; 174.667 14); text = 'Version 14.0.5c Oct 05, 2...'; gestureRecognizers = <NSArray: 0x610000c498a0>; layer = <_UILabelLayer: 0x610000087300>>
   | <UITextView: 0x7f917015ce00; frame = (45 183; 264 403); text = '   •   new Adding new feature...'; clipsToBounds = YES; gestureRecognizers = <NSArray: 0x6100000538f0>; layer = <CALayer: 0x61000042f000>; contentOffset: {0, 0}; contentSize: {264, 890}>
   |    | <<_UITextContainerView: 0x7f9170a13350; frame = (0 0; 264 890); layer = <_UITextTiledLayer: 0x6080002c0930>> minSize = {0, 0}, maxSize = {1.7976931348623157e+308, 1.7976931348623157e+308}, textContainer = <NSTextContainer: 0x610000117b20 size = (264.000000,340282346638528859811704183484516925440.000000); widthTracksTextView = YES; heightTracksTextView = NO>; exclusionPaths = 0x61000001bc30; lineBreakMode = 0>
   |    |    | <_UITileLayer: 0x60800023f8a0> (layer)
   |    |    | <_UITileLayer: 0x60800023f3c0> (layer)
   |    |    | <_UITileLayer: 0x60800023f360> (layer)
   |    |    | <_UITileLayer: 0x60800023eca0> (layer)
   |    | <UIImageView: 0x7f9170a7d370; frame = (-39 397.667; 36 2.33333); alpha = 0; opaque = NO; autoresize = TM; userInteractionEnabled = NO; layer = <CALayer: 0x60800023f4c0>>
   |    | <UIImageView: 0x7f9170a7d560; frame = (258.667 -39; 2.33333 36); alpha = 0; opaque = NO; autoresize = LM; userInteractionEnabled = NO; layer = <CALayer: 0x60800023f5e0>>
   | <UIView: 0x7f916ef149c0; frame = (0 587; 354 0); layer = <CALayer: 0x6100006392a0>>
   | <UIButton: 0x7f91747a8730; frame = (0 0; 0 0); clipsToBounds = YES; opaque = NO; layer = <CALayer: 0x610000639320>>
   |    | <UIButtonLabel: 0x7f916ef00a80; frame = (0 -5.66667; 0 16); text = 'See More Details'; opaque = NO; userInteractionEnabled = NO; layer = <_UILabelLayer: 0x610000084d80>>

你一定已经猜到我的超级视图有 4 个子视图：

  • 一个 stackView （stackView 本身有一个图像和另一个 stackView（这个 stackView 有 2 个自定义标签））
  • 一个 textView
  • 一个视图
  • 一个按钮

这对我来说相当新，但帮助我调试了我的视图的框架（以及文本和类型）。我的子视图之一没有显示在屏幕上，因此使用了 recursiveDescription，我意识到我的子视图之一的宽度是 0...所以我纠正了它的约束，并且子视图出现了。

This a rewriting of this answer:

You must first get the pointer/reference to the object you intend to print all its subviews. Sometimes you may find it easier to find that object by accessing it through its subview. Like po someSubview.superview. This will give you something like:

Optional<UIView>
  ▿ some : <FacebookApp.WhatsNewView: 0x7f91747c71f0; frame = (30 50; 354 636); clipsToBounds = YES; layer = <CALayer: 0x6100002370e0>>
  • FaceBookApp is your app name
  • WhatsNewView is the type of your superview
  • 0x7f91747c71f0 is the pointer to the superview.

To print the superView, you must use breakpoints.

Now to do this step you could just click on the 'view debug hierarchy'. No need for breakpoints

enter image description here

Then you could easily do:

po [0x7f91747c71f0 recursiveDescription]

which for me returned something like:

<FacebookApp.WhatsNewView: 0x7f91747c71f0; frame = (30 50; 354 636); clipsToBounds = YES; layer = <CALayer: 0x6100002370e0>>
   | <UIStackView: 0x7f91747c75f0; frame = (45 60; 264 93); layer = <CATransformLayer: 0x610000230ec0>>
   |    | <UIImageView: 0x7f916ef38c30; frame = (10.6667 0; 243 58); opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0x61000003b840>>
   |    | <UIStackView: 0x7f91747c8230; frame = (44.6667 58; 174.667 35); layer = <CATransformLayer: 0x6100006278c0>>
   |    |    | <FacebookApp.CopyableUILabel: 0x7f91747a80b0; baseClass = UILabel; frame = (44 0; 86.6667 16); text = 'What's New'; gestureRecognizers = <NSArray: 0x610000c4a770>; layer = <_UILabelLayer: 0x610000085550>>
   |    |    | <FacebookApp.CopyableUILabel: 0x7f916ef396a0; baseClass = UILabel; frame = (0 21; 174.667 14); text = 'Version 14.0.5c Oct 05, 2...'; gestureRecognizers = <NSArray: 0x610000c498a0>; layer = <_UILabelLayer: 0x610000087300>>
   | <UITextView: 0x7f917015ce00; frame = (45 183; 264 403); text = '   •   new Adding new feature...'; clipsToBounds = YES; gestureRecognizers = <NSArray: 0x6100000538f0>; layer = <CALayer: 0x61000042f000>; contentOffset: {0, 0}; contentSize: {264, 890}>
   |    | <<_UITextContainerView: 0x7f9170a13350; frame = (0 0; 264 890); layer = <_UITextTiledLayer: 0x6080002c0930>> minSize = {0, 0}, maxSize = {1.7976931348623157e+308, 1.7976931348623157e+308}, textContainer = <NSTextContainer: 0x610000117b20 size = (264.000000,340282346638528859811704183484516925440.000000); widthTracksTextView = YES; heightTracksTextView = NO>; exclusionPaths = 0x61000001bc30; lineBreakMode = 0>
   |    |    | <_UITileLayer: 0x60800023f8a0> (layer)
   |    |    | <_UITileLayer: 0x60800023f3c0> (layer)
   |    |    | <_UITileLayer: 0x60800023f360> (layer)
   |    |    | <_UITileLayer: 0x60800023eca0> (layer)
   |    | <UIImageView: 0x7f9170a7d370; frame = (-39 397.667; 36 2.33333); alpha = 0; opaque = NO; autoresize = TM; userInteractionEnabled = NO; layer = <CALayer: 0x60800023f4c0>>
   |    | <UIImageView: 0x7f9170a7d560; frame = (258.667 -39; 2.33333 36); alpha = 0; opaque = NO; autoresize = LM; userInteractionEnabled = NO; layer = <CALayer: 0x60800023f5e0>>
   | <UIView: 0x7f916ef149c0; frame = (0 587; 354 0); layer = <CALayer: 0x6100006392a0>>
   | <UIButton: 0x7f91747a8730; frame = (0 0; 0 0); clipsToBounds = YES; opaque = NO; layer = <CALayer: 0x610000639320>>
   |    | <UIButtonLabel: 0x7f916ef00a80; frame = (0 -5.66667; 0 16); text = 'See More Details'; opaque = NO; userInteractionEnabled = NO; layer = <_UILabelLayer: 0x610000084d80>>

as you must have guessed my superview has 4 subviews:

  • a stackView (the stackView itself has an image and another stackView(this stackView has 2 custom labels))
  • a textView
  • a view
  • a button

This is fairly new to me, but has helped me debug a my views' frames (and text and type). One of my subviews wasn't showing up on the screen, so used recursiveDescription and I realized the width of my one of my subView's was 0... so I went corrected its constraints and the subview was appearing.

回复 原文
纵山崖 2024-12-09 00:12:22

或者，如果您想从 UIView 扩展返回所有子视图（和嵌套子视图）的数组：

func getAllSubviewsRecursively() -> [AnyObject] {
    var allSubviews: [AnyObject] = []

    for subview in self.subviews {
        if let subview = subview as? UIView {
            allSubviews.append(subview)
            allSubviews = allSubviews + subview.getAllSubviewsRecursively()
        }
    }

    return allSubviews
}

Alternatively if you wanted to return an array of all subviews (and nested subviews) from a UIView Extension:

func getAllSubviewsRecursively() -> [AnyObject] {
    var allSubviews: [AnyObject] = []

    for subview in self.subviews {
        if let subview = subview as? UIView {
            allSubviews.append(subview)
            allSubviews = allSubviews + subview.getAllSubviewsRecursively()
        }
    }

    return allSubviews
}
回复 原文
血之狂魔 2024-12-09 00:12:22

AC# Xamarin 版本：

void ListSubviewsOfView(UIView view)
{
    var subviews = view.Subviews;
    if (subviews.Length == 0) return;

    foreach (var subView in subviews)
    {
        Console.WriteLine("Subview of type {0}", subView.GetType());
        ListSubviewsOfView(subView);
    }
}

或者，如果您想查找我使用的特定类型的所有子视图：

List<T> FindViews<T>(UIView view)
{
    List<T> allSubviews = new List<T>();
    var subviews = view.Subviews.Where(x =>  x.GetType() == typeof(T)).ToList();

    if (subviews.Count == 0) return allSubviews;

       foreach (var subView in subviews)
       {
            allSubviews.AddRange(FindViews<T>(subView));
        }

    return allSubviews;

}

A C# Xamarin version:

void ListSubviewsOfView(UIView view)
{
    var subviews = view.Subviews;
    if (subviews.Length == 0) return;

    foreach (var subView in subviews)
    {
        Console.WriteLine("Subview of type {0}", subView.GetType());
        ListSubviewsOfView(subView);
    }
}

Alternatively, if you want to find all the subviews of a specific type I use:

List<T> FindViews<T>(UIView view)
{
    List<T> allSubviews = new List<T>();
    var subviews = view.Subviews.Where(x =>  x.GetType() == typeof(T)).ToList();

    if (subviews.Count == 0) return allSubviews;

       foreach (var subView in subviews)
       {
            allSubviews.AddRange(FindViews<T>(subView));
        }

    return allSubviews;

}
回复 原文
兔小萌 2024-12-09 00:12:22

我已经在 UIView 的类别中完成了它，只需调用传递索引的函数即可以良好的树格式打印它们。这只是 James Webster 发布的答案的另一个选项。

#pragma mark - Views Tree

- (void)printSubviewsTreeWithIndex:(NSInteger)index
{
    if (!self)
    {
        return;
    }


    NSString *tabSpace = @"";

    @autoreleasepool
    {
        for (NSInteger x = 0; x < index; x++)
        {
            tabSpace = [tabSpace stringByAppendingString:@"\t"];
        }
    }

    NSLog(@"%@%@", tabSpace, self);

    if (!self.subviews)
    {
        return;
    }

    @autoreleasepool
    {
        for (UIView *subView in self.subviews)
        {
            [subView printViewsTreeWithIndex:index++];
        }
    }
}

我希望它有帮助:)

I have done it in a category of UIView just call the function passing the index to print them with a nice tree format. This is just another option of the answer posted by James Webster.

#pragma mark - Views Tree

- (void)printSubviewsTreeWithIndex:(NSInteger)index
{
    if (!self)
    {
        return;
    }


    NSString *tabSpace = @"";

    @autoreleasepool
    {
        for (NSInteger x = 0; x < index; x++)
        {
            tabSpace = [tabSpace stringByAppendingString:@"\t"];
        }
    }

    NSLog(@"%@%@", tabSpace, self);

    if (!self.subviews)
    {
        return;
    }

    @autoreleasepool
    {
        for (UIView *subView in self.subviews)
        {
            [subView printViewsTreeWithIndex:index++];
        }
    }
}

I hope it helps :)

回复 原文
我的黑色迷你裙 2024-12-09 00:12:22
- (NSString *)recusiveDescription:(UIView *)view
{
    NSString *s = @"";
    NSArray *subviews = [view subviews];
    if ([subviews count] == 0) return @"no subviews";

    for (UIView *subView in subviews) {
         s = [NSString stringWithFormat:@"<%@; frame = (%f %f : %f %f) \n ",NSStringFromClass([subView class]), subView.frame.origin.x, subView.frame.origin.y ,subView.frame.size.width, subView.frame.size.height];  
        [self recusiveDescription:subView];
    }
    return s;
}

- (NSString *)recusiveDescription:(UIView *)view
{
    NSString *s = @"";
    NSArray *subviews = [view subviews];
    if ([subviews count] == 0) return @"no subviews";

    for (UIView *subView in subviews) {
         s = [NSString stringWithFormat:@"<%@; frame = (%f %f : %f %f) \n ",NSStringFromClass([subView class]), subView.frame.origin.x, subView.frame.origin.y ,subView.frame.size.width, subView.frame.size.height];  
        [self recusiveDescription:subView];
    }
    return s;
}
回复 原文
谜兔 2024-12-09 00:12:22

self.view.subviews 维护视图的层次结构。要获取 uitableviewcell 的子视图，您必须执行如下操作。

 for (UIView *subView in self.view.subviews) {
      if ([subView isKindOfClass:[UITableView class]]) {
            for (UIView *tableSubview in subView.subviews) {
                .......
            }
      }
 }

self.view.subviews maintain the heirarchy of views.To get subviews of uitableviewcell you have to do something like below.

 for (UIView *subView in self.view.subviews) {
      if ([subView isKindOfClass:[UITableView class]]) {
            for (UIView *tableSubview in subView.subviews) {
                .......
            }
      }
 }
回复 原文
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