比较两个哈希值，如果 ID 不存在则删除
我有两个哈希值，一个看起来像这样：
{:id => "SG_5viWPcG0SLvszXbBxogLkT_51.514568_-0.126244@1300740367",
:name => "Shellys Shoes",
:lat => 51.5145683289,
:lng => -0.1262439936}
这只是一条记录，大约有 80 条，
我的第二个哈希值是：
{"id":"SG_2zNWLdG9147g2ROvNWpDHr_51.512360_0.124480@1300740823",
"lat":51.5123596191,
"lng":-0.1244800016}
上面的哈希值也只是一条记录，但是它是上面的哈希值经过一个API不返回所有记录，仅返回有效记录，我想要做的是将顶部哈希与底部哈希进行比较，并删除底部哈希中不存在的任何记录，
例如，如果id:SG_5viWPcG0SLvszXbBxogLkT_51.514568_-0.126244@1300740367 不在第二个哈希中，然后删除该记录，
我可以比较哈希，但看不到如果 ID 不存在如何删除？
谢谢你们！
编辑： 这些是返回值...
{"points":[{"id":"SG_75oKOgvgFPLjwmdyAKA2rq_51.512825_-0.124655@1300740283","lat":51.5128250122,"lng":-0.1246550009},{"id":"SG_0Sz9CBF5t70tdAffTKYNSg_51.512360_-0.124388@1300740807","lat":51.5123596191,"lng":-0.1243880019},{"id":"SG_2zNWLdG9147g2ROvNWpDHr_51.512360_-0.124480@1300740823","lat":51.5123596191,"lng":-0.1244800016},{"id":"SG_5PvBx89sLPgplapegVJDFv_51.513100_-0.124809@1300740049","lat":51.5130996704,"lng":-0.1248089969},{"id":"SG_4luyHFi5R2f1w3cpjT61ik_51.513393_-0.124556@1300740719","lat":51.5133934021,"lng":-0.1245559976},{"id":"SG_4luyHFi5R2f1w3cpjT61ik_51.513393_-0.124556@1300740719","lat":51.5133934021,"lng":-0.1245559976},{"id":"SG_0pEvrpt7bs42jPAxFSrquC_51.512264_-0.124413@1300740807","lat":51.5122642517,"lng":-0.1244129986},]}
这是原始格式：
[ { :id => "SG_2Km6LX3tEcFwx24eotTHIY_51.513016_-0.123721@1300740411",
:name => "French Connection Group Plc",
:lat => 51.5130157471,
:lng => -0.1237210035
}]
I have two hashes, one looks like this:
{:id => "SG_5viWPcG0SLvszXbBxogLkT_51.514568_-0.126244@1300740367",
:name => "Shellys Shoes",
:lat => 51.5145683289,
:lng => -0.1262439936}
This is just one record, there are about 80,
The second hash I have is:
{"id":"SG_2zNWLdG9147g2ROvNWpDHr_51.512360_0.124480@1300740823",
"lat":51.5123596191,
"lng":-0.1244800016}
The hash above is again just one record, however it is a product of the HASH above after going through an API that does not return all the records, only the valid ones, what I want to do is compare the top hash with the bottom one and delete any records that are not present in the bottom hash,
for example if id:SG_5viWPcG0SLvszXbBxogLkT_51.514568_-0.126244@1300740367 is not in the the second hash then delete that record,
I can compare the hashes, but cant see how to delete if ID is not present?
Thanks guys!
edit:
these are the returned values....
{"points":[{"id":"SG_75oKOgvgFPLjwmdyAKA2rq_51.512825_-0.124655@1300740283","lat":51.5128250122,"lng":-0.1246550009},{"id":"SG_0Sz9CBF5t70tdAffTKYNSg_51.512360_-0.124388@1300740807","lat":51.5123596191,"lng":-0.1243880019},{"id":"SG_2zNWLdG9147g2ROvNWpDHr_51.512360_-0.124480@1300740823","lat":51.5123596191,"lng":-0.1244800016},{"id":"SG_5PvBx89sLPgplapegVJDFv_51.513100_-0.124809@1300740049","lat":51.5130996704,"lng":-0.1248089969},{"id":"SG_4luyHFi5R2f1w3cpjT61ik_51.513393_-0.124556@1300740719","lat":51.5133934021,"lng":-0.1245559976},{"id":"SG_4luyHFi5R2f1w3cpjT61ik_51.513393_-0.124556@1300740719","lat":51.5133934021,"lng":-0.1245559976},{"id":"SG_0pEvrpt7bs42jPAxFSrquC_51.512264_-0.124413@1300740807","lat":51.5122642517,"lng":-0.1244129986},]}
This is the original format:
[ { :id => "SG_2Km6LX3tEcFwx24eotTHIY_51.513016_-0.123721@1300740411",
:name => "French Connection Group Plc",
:lat => 51.5130157471,
:lng => -0.1237210035
}]
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您可以从返回的值中收集有效 ID 的列表，如下所示：
然后，您可以使用以下方式从原始值中删除无效值：
You can collect a list of the valid IDs from the returned values with something like:
You can then remove the invalid values from the original with something like: