获取日期范围的十进制月份数

发布于 2024-12-01 20:34:37 字数 1215 浏览 0 评论 0原文

我尝试获取日期范围的十进制月份数。示例：

ruby-1.9.2-p0 > from = Date.new(2011, 7, 6)
 => Wed, 06 Jul 2011 
ruby-1.9.2-p0 > to = Date.new(2011, 8, 31)
 => Wed, 31 Aug 2011 
ruby-1.9.2-p0 > to - from
 => (56/1)

所以差异是 56 天。但我想要并且需要几个月的时间： 1.83

我创建了以下代码片段，它返回正确的结果，但感觉不像 ruby 方式：

months = Hash.new
(from..to).each do |date|
  unless months.key? date.beginning_of_month
    months[date.beginning_of_month] = 1
  else
    months[date.beginning_of_month] += 1
  end
end

multiplicator = 0.0
months.each do |month, days|
  multiplicator += days.to_f/month.end_of_month.day
end

return multiplicator.floor_to(2)

说实话：它看起来很丑陋而且效率很低。但我就是想不出任何更简单的方法。你能帮我找到更好的解决方案吗？

如有更多问题，请随时问我。

非常感谢！

更新/解决方案：使用以下代码解决了问题：

months = 0.0

months += ((date_to < date_from.end_of_month ? date_to : date_from.end_of_month) - date_from + 1) / Time.days_in_month(date_from.month)
unless date_to.month == date_from.month
  months += (date_to - date_to.beginning_of_month + 1) / Time.days_in_month(date_to.month)
  months += date_to.month - date_from.month - 1
end

return months.floor_to(2)

原文

I try to get a decimal amount of months for a date range. Example:

ruby-1.9.2-p0 > from = Date.new(2011, 7, 6)
 => Wed, 06 Jul 2011 
ruby-1.9.2-p0 > to = Date.new(2011, 8, 31)
 => Wed, 31 Aug 2011 
ruby-1.9.2-p0 > to - from
 => (56/1)

So the difference is 56 days. But I want and need the amount of months: 1.83

I have created the following piece of code which returns the correct result but doesn't feel like the ruby way:

months = Hash.new
(from..to).each do |date|
  unless months.key? date.beginning_of_month
    months[date.beginning_of_month] = 1
  else
    months[date.beginning_of_month] += 1
  end
end

multiplicator = 0.0
months.each do |month, days|
  multiplicator += days.to_f/month.end_of_month.day
end

return multiplicator.floor_to(2)

To be honest: It looks ugly and really inefficient. But I just cannot figure out any easier way.
Can you help me to find a better solution?

For further questions feel free to ask me.

Many thanks in advance!

Update/Solution: Solved the problem with the following piece of code:

months = 0.0

months += ((date_to < date_from.end_of_month ? date_to : date_from.end_of_month) - date_from + 1) / Time.days_in_month(date_from.month)
unless date_to.month == date_from.month
  months += (date_to - date_to.beginning_of_month + 1) / Time.days_in_month(date_to.month)
  months += date_to.month - date_from.month - 1
end

return months.floor_to(2)

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