在gas宏中自动生成xmm寄存器名称?
我想编写一个gas宏来生成包含各种movdqu指令的代码到xmm寄存器,具体取决于参数n。
.macro xxmov n, p1
.if (\n == 1)
xor %eax, %eax
.endif
.if (\n - 1)
xxmov (\n - 1), \p1
.endif
movdqu ((\n - 1)*0x10)(\p1), %xmm0
.endm
xxmov 14, %rsi
编译后,反汇编代码是,
0000000000000000 <.text>:
0: 31 c0 xor %eax,%eax
2: f3 0f 6f 06 movdqu (%rsi),%xmm0
6: f3 0f 6f 46 10 movdqu 0x10(%rsi),%xmm0
b: f3 0f 6f 46 20 movdqu 0x20(%rsi),%xmm0
10: f3 0f 6f 46 30 movdqu 0x30(%rsi),%xmm0
15: f3 0f 6f 46 40 movdqu 0x40(%rsi),%xmm0
1a: f3 0f 6f 46 50 movdqu 0x50(%rsi),%xmm0
1f: f3 0f 6f 46 60 movdqu 0x60(%rsi),%xmm0
24: f3 0f 6f 46 70 movdqu 0x70(%rsi),%xmm0
29: f3 0f 6f 86 80 00 00 movdqu 0x80(%rsi),%xmm0
30: 00
31: f3 0f 6f 86 90 00 00 movdqu 0x90(%rsi),%xmm0
38: 00
39: f3 0f 6f 86 a0 00 00 movdqu 0xa0(%rsi),%xmm0
40: 00
41: f3 0f 6f 86 b0 00 00 movdqu 0xb0(%rsi),%xmm0
48: 00
49: f3 0f 6f 86 c0 00 00 movdqu 0xc0(%rsi),%xmm0
50: 00
51: f3 0f 6f 86 d0 00 00 movdqu 0xd0(%rsi),%xmm0
58: 00
但是,当我在上面的 xxmov 宏中将 %xmm0 替换为 %xmm\n 时,出现编译错误,
$ gcc -c mac.s
mac.s: Assembler messages:
mac.s:17: Error: bad register name `%xmm(((((((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((((14 - 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((((14 - 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((14 - 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((14 - 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((14 - 1)- 1)'
mac.s:17: Error: bad register name `%xmm(14 - 1)'
因此,无论如何,我可以将宏操作为 xmm 寄存器名称(从 %xmm0 到%xmm_{n-1})?我已经尝试过 http://sourceware 中提到的 \@ (%xmm\@)。 org/binutils/docs/as/Macro.html#Macro。但是,它工作得不太好,因为我想多次使用这个宏,而 \@ 似乎是单调递增的。
I would like to write a gas macro to generate code containing various movdqu instructions to xmm register depending on the parameter n.
.macro xxmov n, p1
.if (\n == 1)
xor %eax, %eax
.endif
.if (\n - 1)
xxmov (\n - 1), \p1
.endif
movdqu ((\n - 1)*0x10)(\p1), %xmm0
.endm
xxmov 14, %rsi
Once compiled, the disassembled code is,
0000000000000000 <.text>:
0: 31 c0 xor %eax,%eax
2: f3 0f 6f 06 movdqu (%rsi),%xmm0
6: f3 0f 6f 46 10 movdqu 0x10(%rsi),%xmm0
b: f3 0f 6f 46 20 movdqu 0x20(%rsi),%xmm0
10: f3 0f 6f 46 30 movdqu 0x30(%rsi),%xmm0
15: f3 0f 6f 46 40 movdqu 0x40(%rsi),%xmm0
1a: f3 0f 6f 46 50 movdqu 0x50(%rsi),%xmm0
1f: f3 0f 6f 46 60 movdqu 0x60(%rsi),%xmm0
24: f3 0f 6f 46 70 movdqu 0x70(%rsi),%xmm0
29: f3 0f 6f 86 80 00 00 movdqu 0x80(%rsi),%xmm0
30: 00
31: f3 0f 6f 86 90 00 00 movdqu 0x90(%rsi),%xmm0
38: 00
39: f3 0f 6f 86 a0 00 00 movdqu 0xa0(%rsi),%xmm0
40: 00
41: f3 0f 6f 86 b0 00 00 movdqu 0xb0(%rsi),%xmm0
48: 00
49: f3 0f 6f 86 c0 00 00 movdqu 0xc0(%rsi),%xmm0
50: 00
51: f3 0f 6f 86 d0 00 00 movdqu 0xd0(%rsi),%xmm0
58: 00
However, when I replaced %xmm0 with %xmm\n in the above xxmov macro, I got compiling error,
$ gcc -c mac.s
mac.s: Assembler messages:
mac.s:17: Error: bad register name `%xmm(((((((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((((((14 - 1)- 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((((14 - 1)- 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((((14 - 1)- 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((((14 - 1)- 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm(((14 - 1)- 1)- 1)'
mac.s:17: Error: bad register name `%xmm((14 - 1)- 1)'
mac.s:17: Error: bad register name `%xmm(14 - 1)'
So, it there anyway I can manipulate my macro to xmm register name (from %xmm0 to %xmm_{n-1})? I have tried \@ (%xmm\@) mentioned in http://sourceware.org/binutils/docs/as/Macro.html#Macro. However, it didn't work very well because I would like to use this macro multiple time, while \@ seems to be monotonically increasing..
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与其倒数,不如保留一个变量来向上计数怎么样?像这样:
生成:
更新:哎呀,这只适用于文件中的第一个宏用法。如果您需要在同一个文件中多次使用它,看起来使用
.altmacro
语法是可行的方法(可以使用.noaltmacro
再次关闭它) >):How about rather than counting down you keep a variable to count up? Like this:
Which generates:
Update: Oops, that only works for the first macro usage in the file. If you need to use it more than once in the same file, it looks like using the
.altmacro
syntax is the way to go (it can be turned off again with.noaltmacro
):