匿名类方法参数如何返回到原来的实例化类？

发布于 2024-12-01 17:55:49 字数 330 浏览 0 评论 0原文

这是我的代码：

public void pollLocation()
{
    myLocation.getLocation(this, new LocationResult()
    {
        public void gotLocation(Location location)
        {
            //I want to assign Location object from here...
        }
    });
}

private Location lastLocation; //...to here.

这可能吗？

原文

Here's my code:

public void pollLocation()
{
    myLocation.getLocation(this, new LocationResult()
    {
        public void gotLocation(Location location)
        {
            //I want to assign Location object from here...
        }
    });
}

private Location lastLocation; //...to here.

Is this possible?

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岁月无声 2024-12-08 17:55:49

是的。一般来说，您可以只写

lastLocation = location

但也许 LocationResult 类/接口也有一个名为 lastLocation 的字段。在这种情况下，您必须编写

OuterClassName.this.lastLocation = location

But 由于看起来您会执行一些异步轮询，因此在没有同步的情况下执行此操作太危险了。此外，您也不会注意到 LastLocation 何时被设置。所以最好在外部类中使用同步setter。

Yes. Generally you can just write

lastLocation = location

But maybe the LocationResult class/interface also has a field named lastLocation. In this case you have to write

OuterClassName.this.lastLocation = location

But since it looks like you would do some asynchronous polling, it's too dangerous to do this without synchronization. Also you wouldn't notice when the lastLocation gets set. So it's better to use a synchronized setter in the outer class.

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千仐 2024-12-08 17:55:49

您可以使用设置器：

public void pollLocation()
{
    myLocation.getLocation(this, new LocationResult()
    {
        public void gotLocation(Location location)
        {
            //I want to assign Location object from here...
            setLastLocation(...);
        }
    });
}

private Location lastLocation; //...to here.
private void setLastLocation(Location l) { lastLocation = l; }

只需小心多线程问题。如果您使用多个线程，最好声明lastLocation volatile 或使用AtomicReference。否则，您的代码可能无法按您的预期工作。

You could use a setter:

public void pollLocation()
{
    myLocation.getLocation(this, new LocationResult()
    {
        public void gotLocation(Location location)
        {
            //I want to assign Location object from here...
            setLastLocation(...);
        }
    });
}

private Location lastLocation; //...to here.
private void setLastLocation(Location l) { lastLocation = l; }

Just be careful about multithreading issues. If you are using multiple threads, you'd better declare lastLocation volatile or use an AtomicReference. Otherwise, your code might not work as you expect.

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