我们可以有一个虚静态方法吗？ (c++)
可能的重复：
C++ 静态虚拟成员？
我们可以有一个虚拟静态方法（在 C++ 中）吗？我尝试编译以下内容 代码：
#include <iostream>
using namespace std;
class A
{
public:
virtual static void f() {cout << "A's static method" << endl;}
};
class B :public A
{
public:
static void f() {cout << "B's static method" << endl;}
};
int main()
{
/* some code */
return 0;
}
但编译器说：
member 'f' cannot be declared both virtual and static
所以我猜答案是否定的，但为什么呢？
谢谢 ， 罗恩
Possible Duplicate:
C++ static virtual members?
Can we have a virtual static method (in C++) ? I've tried to compile the following
code :
#include <iostream>
using namespace std;
class A
{
public:
virtual static void f() {cout << "A's static method" << endl;}
};
class B :public A
{
public:
static void f() {cout << "B's static method" << endl;}
};
int main()
{
/* some code */
return 0;
}
but the compiler says that :
member 'f' cannot be declared both virtual and static
so I guess the answer is no , but why ?
thanks ,
Ron
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评论（4）
不。类中函数的
static意味着该函数不需要对象来操作。虚拟意味着实现取决于调用对象的类型。对于 static 来说，没有调用对象，因此在同一个函数上同时使用static和virtual是没有意义的。
No.
staticon a function in a class means that the function doesn't need an object to operate on.virtualmeans the implementation depends on the type of the calling object. For static there is no calling object, so it doesn't make sense to have bothstaticandvirtualon the same function.
不要认为这是可能的，因为您可以在没有对象 A 的情况下调用
A::F();。使其虚拟和静态意味着矛盾。
Don't think this is possible because you could call
A::F();without having the object A.Making it virtual and static would mean a contradiction.
不，
static函数就像全局函数，但也在类命名空间内。virtual意味着在派生类中继承和重新实现 - 您无法重新实现“全局”函数。No,
staticfunction is like global function, but also inside class namespace.virtualimplies inheritance and reimplementing in derived class - you can't reimplement 'global' function.因为该类没有
this指针。里面有虚函数查找表。快速谷歌一下可以告诉你更多关于虚函数查找表的信息。Because the class doesn't have a
thispointer. In there is the virtual function lookup table. A quick google can tell you more about the virtual function lookup table.