奇怪的编译器错误：“未定义对‘main’的引用”
有人能告诉我这是什么意思吗？
/usr/lib/i386-linux-gnu/gcc/i686-linux-gnu/4.5.2/../../../crt1.o: In function `_start':
(.text+0x18): undefined reference to `main'
collect2: ld returned 1 exit status
make: *** [program] Error 1
我的 make 文件如下所示：
program : main.o render.o screenwriter.o
g++ -o main.o render.o screenwriter.o -lSDL
main.o : main.cpp render.h screenwriter.h
g++ -c main.cpp render.h screenwriter.h -lSDL
render.o : render.h render.cpp
g++ -c render.h render.cpp -lSDL
screenwriter.o : screenwriter.h screenwriter.cpp
g++ -c screenwriter.h screenwriter.cpp -lSDL
clean:
rm program main.o render.o screenwriter.o -lSDL
谢谢。
Could someone tell me what this means?
/usr/lib/i386-linux-gnu/gcc/i686-linux-gnu/4.5.2/../../../crt1.o: In function `_start':
(.text+0x18): undefined reference to `main'
collect2: ld returned 1 exit status
make: *** [program] Error 1
My make file looks like as follows:
program : main.o render.o screenwriter.o
g++ -o main.o render.o screenwriter.o -lSDL
main.o : main.cpp render.h screenwriter.h
g++ -c main.cpp render.h screenwriter.h -lSDL
render.o : render.h render.cpp
g++ -c render.h render.cpp -lSDL
screenwriter.o : screenwriter.h screenwriter.cpp
g++ -c screenwriter.h screenwriter.cpp -lSDL
clean:
rm program main.o render.o screenwriter.o -lSDL
Thanks.
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第一条规则应该是
假设您想要将
main.o render.o screenwriter.o链接到名为program的可执行文件中。此外，在编译步骤 ( -c ) 中
-lDSL位没有用，它是链接器指令。That first rule should be
Assuming that you want to link
main.o render.o screenwriter.ointo an executable calledprogramAlso, in the compile steps ( -c ) the
-lDSLbit is not useful, it's a linker instruction.将第二行更改为：
否则，您的输出是main.o，并且您在输入中丢失了它。
比手动维护牺牲更好的是使用特殊宏：
因此，即使您扩展程序，您也不必再次编辑该命令。
Change the second line to:
Otherwise your output is main.o and you're missing it in the input.
Even better than manual maintenance martyrdom is to use special macros:
So even when you expand your program, you won't have to edit that command again.