帮助用 Python 封装命令行工具

发布于 2024-12-01 12:23:11 字数 711 浏览 2 评论 0原文

我真的遇到了一个问题，我希望有人可以帮助我。我正在尝试在 Python3.1 中为名为 spooky 的命令行程序创建一个包装器。我可以在命令行上成功运行这个程序，如下所示：

$ spooky -a 4 -b .97

我对 spooky 的第一次 Python 包装尝试如下所示：

import subprocess

start = "4"
end = ".97"

spooky_path = '/Users/path/to/spooky'
cmd = [spooky_path, '-a', start, '-b', end]
process = subprocess.Popen(cmd, stdout=subprocess.PIPE)
process.wait()
print('Done')

上面的代码打印 Done，但不执行程序 spooky

接下来我尝试在命令行上执行程序，如下所示：

$ /Users/path/to/spooky -a 4 -b .97

上面的代码也失败了，并且没有提供任何有用的错误。

我的问题是：如何通过向命令行发送 spooky -a 4 -b .97 来让 Python 运行该程序？我非常感谢您能提供的任何帮助。提前致谢。

原文

I'm really stuck with a problem I'm hoping someone can help me with. I'm trying to create a wrapper in Python3.1 for a command line program called spooky. I can successfully run this program on the command line like this:

$ spooky -a 4 -b .97

My first Python wrapper attempt for spooky looked like this:

import subprocess

start = "4"
end = ".97"

spooky_path = '/Users/path/to/spooky'
cmd = [spooky_path, '-a', start, '-b', end]
process = subprocess.Popen(cmd, stdout=subprocess.PIPE)
process.wait()
print('Done')

The above code prints Done, but does not execute the program spooky

Next I tried to just execute the program on the command line like this:

$ /Users/path/to/spooky -a 4 -b .97

The above code also fails, and provides no helpful errors.

My question is: How can I get Python to run this program by sending spooky -a 4 -b .97 to the command line? I would VERY much appreciate any help you can provide. Thanks in advance.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

人事已非 2024-12-08 12:23:12

尝试将命令变成单个字符串：

cmd = 'spooky_path -a start -b end'
process = subprocess.Popen(cmd, shell=True)

Try making your command into a single string:

cmd = 'spooky_path -a start -b end'
process = subprocess.Popen(cmd, shell=True)

回复收藏 0 原文

喵星人汪星人 2024-12-08 12:23:11

您需要删除 stdout=subprocess.PIPE。这样做会断开进程的 stdout 与 Python 的 stdout 的连接，并使其可以使用 Popen.communicate() 函数检索，如下所示：

import subprocess

spooky_path = 'ls'
cmd = [spooky_path, '-l']
process = subprocess.Popen(cmd, stdout=subprocess.PIPE)
output = process.communicate()[0]
print "Output:", output
process.wait()
print('Done')

要使其直接打印，您可以在不使用 stdout 参数的情况下使用它：

process = subprocess.Popen(cmd)

或者您可以使用 call 函数：

process = subprocess.call(cmd)

You need to drop the stdout=subprocess.PIPE. Doing that disconnects the stdout of your process from Python's stdout and makes it retrievable using the Popen.communicate() function, like so:

import subprocess

spooky_path = 'ls'
cmd = [spooky_path, '-l']
process = subprocess.Popen(cmd, stdout=subprocess.PIPE)
output = process.communicate()[0]
print "Output:", output
process.wait()
print('Done')

To make it print directly you can use it without the stdout argument: