Java 中使用 HTTPClient 的 GZip POST 请求

发布于 2024-12-01 09:05:46 字数 132 浏览 2 评论 0原文

我需要向 Web 服务器发送 POST 请求，其中包含压缩的请求参数。我正在使用 Apache HttpClient，并且我读到它支持开箱即用的 Gzip，但我找不到任何有关如何执行我需要的操作的示例。如果有人可以发布一些这方面的例子，我将不胜感激。

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阿楠 2024-12-08 09:05:46

您需要首先将该 String 转换为 gzipped byte[] 或（temp）File。假设它不是一个非常大的 String 值，因此 byte[] 对于可用的 JVM 内存来说足够安全：

String foo = "value";
ByteArrayOutputStream baos = new ByteArrayOutputStream();

try (GZIPOutputStream gzos = new GZIPOutputStream(baos)) {
    gzos.write(foo.getBytes("UTF-8"));
}

byte[] fooGzippedBytes = baos.toByteArray();

然后，您可以使用以下命令将其作为多部分主体发送： HttpClient如下：

MultipartEntity entity = new MultipartEntity();
entity.addPart("foo", new InputStreamBody(new ByteArrayInputStream(fooGzippedBytes), "foo.txt"));

HttpPost post = new HttpPost("http://example.com/some");
post.setEntity(entity);

HttpClient client = new DefaultHttpClient();
HttpResponse response = client.execute(post);
// ...

注意HttpClient 4.1支持新的ByteArrayBody< /code>可以按如下方式使用：

entity.addPart("foo", new ByteArrayBody(fooGzippedBytes, "foo.txt"));

You need to turn that String into a gzipped byte[] or (temp) File first. Let's assume that it's not an extraordinary large String value so that a byte[] is safe enough for the available JVM memory:

String foo = "value";
ByteArrayOutputStream baos = new ByteArrayOutputStream();

try (GZIPOutputStream gzos = new GZIPOutputStream(baos)) {
    gzos.write(foo.getBytes("UTF-8"));
}

byte[] fooGzippedBytes = baos.toByteArray();

Then, you can send it as a multipart body using HttpClient as follows:

MultipartEntity entity = new MultipartEntity();
entity.addPart("foo", new InputStreamBody(new ByteArrayInputStream(fooGzippedBytes), "foo.txt"));

HttpPost post = new HttpPost("http://example.com/some");
post.setEntity(entity);

HttpClient client = new DefaultHttpClient();
HttpResponse response = client.execute(post);
// ...

Note that HttpClient 4.1 supports the new ByteArrayBody which can be used as follows:

entity.addPart("foo", new ByteArrayBody(fooGzippedBytes, "foo.txt"));

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两相知 2024-12-08 09:05:46

尝试 GzipCompressingEntity 类。如果我要压缩帖子的正文，例如 JSON 对象，我会去：

    // json payload
if (jsonBody != null) {
    
    post.setHeader("Content-Type", "application/json");
    StringEntity requestEntity = new StringEntity( jsonBody, ContentType.APPLICATION_JSON);
    
    if (gzipBody) {
        GzipCompressingEntity gzippedEntity = new GzipCompressingEntity(requestEntity);
        post.setEntity(gzippedEntity);
    }else {
        post.setEntity(requestEntity);
    }
    
}

尚未测试，但我假设要添加参数，您会这样做：

    // add parameters
if (parameters != null && parameters.length > 0){

    List<NameValuePair> urlParameters = new ArrayList<NameValuePair>();
    for (int i = 0; i < parameters.length; i++){
        urlParameters.add(new BasicNameValuePair(parameters[i][0], parameters[i][1]));
    }
    post.setEntity(new GzipCompressingEntity(new UrlEncodedFormEntity(urlParameters)));
}

Try the GzipCompressingEntity class. If I'm zipping the body of a post e.g. for a JSON object I would go:

    // json payload
if (jsonBody != null) {
    
    post.setHeader("Content-Type", "application/json");
    StringEntity requestEntity = new StringEntity( jsonBody, ContentType.APPLICATION_JSON);
    
    if (gzipBody) {
        GzipCompressingEntity gzippedEntity = new GzipCompressingEntity(requestEntity);
        post.setEntity(gzippedEntity);
    }else {
        post.setEntity(requestEntity);
    }
    
}

Haven't tested but I assume for adding parameters you'd do:

    // add parameters
if (parameters != null && parameters.length > 0){

    List<NameValuePair> urlParameters = new ArrayList<NameValuePair>();
    for (int i = 0; i < parameters.length; i++){
        urlParameters.add(new BasicNameValuePair(parameters[i][0], parameters[i][1]));
    }
    post.setEntity(new GzipCompressingEntity(new UrlEncodedFormEntity(urlParameters)));
}

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