从 NSString 中删除 http://

Question

如何从 NSString 中删除某些文本，例如“http://”？它需要完全按照这个顺序。感谢您的帮助！

这是我正在使用的代码，但是 http:// 并未删除。相反，它会显示 http://http://www.example.com。我应该怎么办？谢谢！

NSString *urlAddress = addressBar.text;
[urlAddress stringByReplacingOccurrencesOfString:@"http://" withString:@""];
urlAddress = [NSString stringWithFormat:@"http://%@", addressBar.text];
NSLog(@"The user requested this host name: %@", urlAddress);

Answer 1

像这样？

NSString* stringWithoutHttp = [someString stringByReplacingOccurrencesOfString:@"http://" withString:@""];

（如果您只想删除开头的文本，请执行 jtbandes 所说的操作 - 上面的代码也将替换字符串中间出现的文本）

Answer 2

这是一个处理 http 和 http 的解决方案。 https：

    NSString *shortenedURL = url.absoluteURL;

    if ([shortenedURL hasPrefix:@"https://"]) shortenedURL = [shortenedURL substringFromIndex:8];
    if ([shortenedURL hasPrefix:@"http://"]) shortenedURL = [shortenedURL substringFromIndex:7];

Answer 3

NSString *newString = [myString stringByReplacingOccurrencesOfString:@"http://"
                                                          withString:@""
                                                             options:NSAnchoredSearch // beginning of string
                                                               range:NSMakeRange(0, [myString length])]

Answer 4

如果 http:// 位于字符串的开头，您可以使用

 NSString *newString  = [yourOriginalString subStringFromIndex:7];

或者按照 SVD 建议

编辑：看到问题后编辑

将此行更改

[urlAddress stringByReplacingOccurrencesOfString:@"http://" withString:@""];

为

urlAddress  = [urlAddress stringByReplacingOccurrencesOfString:@"http://" withString:@""];

Answer 5

另一种方法是：

NSString *str = @"http//abc.com";  
NSArray *arr = [str componentSeparatedByString:@"//"];  
NSString *str1 = [arr objectAtIndex:0];       //   http  
NSString *str2 = [arr objectAtIndex:1];       //   abc.com

Answer 6

由于该线程仍然处于活动状态并出现在我的搜索中，以从 URL（不是 NSString）中删除前缀...如果您从 URL 开始，则会有一行：

String(url.absoluteString.dropFirst((url.scheme?.count ?? -3) + 3))

Answer 7

这是另一种选择；

NSMutableString *copiedUrl = [[urlAddress mutablecopy] autorelease];
[copiedUrl deleteCharactersInRange: [copiedUrl rangeOfString:@"http://"]];

Answer 8

如果您希望修剪两侧并编写更少的代码：

NSString *webAddress = @"http://www.google.co.nz";

// add prefixes you'd like to filter out here
NSArray *prefixes = [NSArray arrayWithObjects:@"https:", @"http:", @"//", @"/", nil];

for (NSString *prefix in prefixes)
    if([webAddress hasPrefix:prefix]) webAddress = [webAddress stringByReplacingOccurrencesOfString:prefix withString:@"" options:NSAnchoredSearch range:NSMakeRange(0, [webAddress length])];

// add suffixes you'd like to filter out here
NSArray *suffixes = [NSArray arrayWithObjects:@"/", nil];

for (NSString *suffix in suffixes)
    if([webAddress hasSuffix:suffix]) webAddress = [webAddress stringByReplacingOccurrencesOfString:suffix withString:@"" options:NSBackwardsSearch range:NSMakeRange(0, [webAddress length])];

此代码将从前面删除指定的前缀并从后面删除后缀（如尾部斜杠）。只需向前缀/后缀数组添加更多子字符串即可过滤更多内容。

Answer 9

Swift 3

用于替换所有出现的位置：

let newString = string.replacingOccurrences(of: "http://", with: "")

用于替换字符串开头的出现位置：

let newString = string.replacingOccurrences(of: "http://", with: "", options: .anchored)

Answer 10

对于那些使用 swift 并已经到达这里的人。

extension String {

   func withoutHttpPrefix() -> String {
       var idx: String.Index?;
       if self.hasPrefix("http://www.") {
          idx = self.index(startIndex, offsetBy: 11)
       } else if hasPrefix("https://www.") {
           idx = self.index(startIndex, offsetBy: 12)
       } else if self.hasPrefix("http://") {
          idx = self.index(startIndex, offsetBy: 7)
       } else if hasPrefix("https://") {
           idx = self.index(startIndex, offsetBy: 8)
       }

       if idx != nil {
           return String(self[idx!...])
       }
       return self
   }
}

Answer 11

此字符串扩展添加了一个 removeHTTPPrefix() 方法，该方法通过拆分字符串从 URL 中删除 http:// 或 https:// 前缀位于 :// 并返回其后的部分，如果未找到分隔符则返回原始字符串：

extension String {    
   func removeHTTPPrefix() -> String {
       return self.components(separatedBy: "://").last ?? self
   }
}

let url = "https://example.com"
let result = url.removeHTTPPrefix()
// result: "example.com"

let plainString = "example.com"
let result2 = plainString.removeHTTPPrefix()
// result2: "example.com" (no change, since there's no "http://" or "https://")

Answer 12

或者

+(NSString*)removeOpeningTag:(NSString*)inString tag:(NSString*)inTag {
    if ([inString length] == 0 || [inTag length] == 0) return inString;
    if ([inString length] < [inTag length]) {return inString;}
    NSRange tagRange= [inString rangeOfString:inTag];   
    if (tagRange.location == NSNotFound || tagRange.location != 0) return inString; 
    return [inString substringFromIndex:tagRange.length]; 
}

Answer 13

NSString* newString = [string stringByReplacingOccurrencesOfString:@"http://" withString:@""];

Answer 14

一种更通用的方法：

- (NSString*)removeURLSchemeFromStringURL:(NSString*)stringUrl {
    NSParameterAssert(stringUrl);
    static NSString* schemeDevider = @"://";

    NSScanner* scanner = [NSScanner scannerWithString:stringUrl];
    [scanner scanUpToString:schemeDevider intoString:nil];

    if (scanner.scanLocation <= stringUrl.length - schemeDevider.length) {
        NSInteger beginLocation = scanner.scanLocation + schemeDevider.length;
        stringUrl = [stringUrl substringWithRange:NSMakeRange(beginLocation, stringUrl.length - beginLocation)];
    }

    return stringUrl;
}

Answer 15

大家好，有点晚了，但我有一个通用的方法
比方说：

NSString *host = @"ssh://www.somewhere.com";
NSString *scheme = [[[NSURL URLWithString:host] scheme] stringByAppendingString:@"://"]; 
// This extract ssh and add :// so we get @"ssh://" note that this code handle any scheme http, https, ssh, ftp ....
NSString *stripHost = [host stringByReplacingOccurrencesOfString:scheme withString:@""]; 
// Result : stripHost = @"www.somewhere.com"

Answer 16

这将删除任何方案，包括 http、https 等。

NSRange dividerRange = [str rangeOfString:@"://"];
NSString *newString = [str substringFromIndex:NSMaxRange(dividerRange)];