在 SQL 更新中使用 Distinct

Question

这是我需要转换为更新的选择：

SELECT DISTINCT f.SectionID, f.Name, v.Enabled
FROM SETTING_VALUE v
INNER JOIN SETTING s ON v.SettingID = s.SettingID
INNER JOIN LU_FIELD f ON f.FieldID = s.FieldID
WHERE v.DisplayValue LIKE '%Miami%'
AND f.ControlName LIKE '%City%'

我的尝试：

UPDATE SETTING_VALUE
SET Enabled = 0
FROM SETTING_VALUE v
INNER JOIN SETTING s ON v.SettingID = s.SettingID
INNER JOIN LU_FIELD f ON f.FieldID = s.FieldID
WHERE v.DisplayValue LIKE '%Miami%'
AND f.ControlName LIKE '%City%'

不确定如何应用不同

Answer 1

根据您的评论，所有匹配的行都应该更新，您不需要不同。只需执行此操作：

UPDATE SETTING_VALUE
SET Enabled = 0
FROM SETTING_VALUE v
INNER JOIN SETTING s ON v.SettingID = s.SettingID
INNER JOIN LU_FIELD f ON f.FieldID = s.FieldID
WHERE v.DisplayValue LIKE '%Miami%'
AND f.ControlName LIKE '%City%'

您在选择中看到的所有内容都将被更新。

Answer 2

选项 1：使用临时表来保存初始查询结果，然后根据查询结果进行更新。

选项2：

Insert into SETTING_VALUE
(SectionID, Name, Enabled)
SELECT DISTINCT f.SectionID, f.Name, v.Enabled
FROM SETTING_VALUE v
INNER JOIN SETTING s ON v.SettingID = s.SettingID
INNER JOIN LU_FIELD f ON f.FieldID = s.FieldID
WHERE v.DisplayValue LIKE '%Miami%'
AND f.ControlName LIKE '%City%'

Answer 3

UPDATE SETTING_VALUE
   SET Enabled = 0
 WHERE DisplayValue LIKE '%Miami%'
       AND EXISTS (
                   SELECT *
                     FROM SETTING s 
                    WHERE SETTING_VALUE.SettingID = s.SettingID
                          AND EXISTS (
                                      SELECT *
                                        FROM LU_FIELD f 
                                       WHERE f.FieldID = s.FieldID
                                             AND f.ControlName LIKE '%City%'
                                     )
                  );

Answer 4

您可以尝试以下方法

UPDATE v
SET Enabled = 0 
FROM SETTING_VALUE v 
WHERE EXISTS(
   select * from SETTING s 
   INNER JOIN LU_FIELD f ON f.FieldID = s.FieldID 
   WHERE v.DisplayValue LIKE '%Miami%' 
   AND f.ControlName LIKE '%City%' 
   AND v.SettingID = s.SettingID
)