Python 中的持久 HTTPS 连接

发布于 2024-12-01 06:20:23 字数 343 浏览 6 评论 0原文

我想向实时流发出 HTTPS 请求并保持连接打开，以便我可以继续从中读取内容并进行处理。

我想用 python 编写脚本。我不确定如何在我的脚本中保持连接打开。我已经使用curl 测试了端点，它使连接成功保持打开状态。但我该如何在Python中做到这一点。目前，我有以下代码：

c = httplib.HTTPSConnection('userstream.twitter.com')
c.request("GET", "/2/user.json?" + req.to_postdata())
response = c.getresponse()

我从这里去哪里？

谢谢！

原文

I want to make an HTTPS request to a real-time stream and keep the connection open so that I can keep reading content from it and processing it.

I want to write the script in python. I am unsure how to keep the connection open in my script. I have tested the endpoint with curl which keeps the connection open successfully. But how do I do it in Python. Currently, I have the following code:

c = httplib.HTTPSConnection('userstream.twitter.com')
c.request("GET", "/2/user.json?" + req.to_postdata())
response = c.getresponse()

Where do I go from here?

Thanks!

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月依秋水 2024-12-08 06:20:23

看起来您的实时流是作为一个无休止的 HTTP GET 响应来传递的，是吗？如果是这样，你可以使用 python 的内置 urllib2.urlopen() 。它返回一个类似文件的对象，您可以从中读取任意数量的数据，直到服务器挂断为止。

f=urllib2.urlopen('https://encrypted.google.com/')
while True:
    data = f.read(100)
    print(data)

请记住，虽然 urllib2 使用 https，但它不会验证服务器证书，因此您可能需要尝试添加像 pycurl 或 urlgrabber 以获得更好的安全性。（我不确定 urlgrabber 是否支持 https。）

It looks like your real-time stream is delivered as one endless HTTP GET response, yes? If so, you could just use python's built-in urllib2.urlopen(). It returns a file-like object, from which you can read as much as you want until the server hangs up on you.

f=urllib2.urlopen('https://encrypted.google.com/')
while True:
    data = f.read(100)
    print(data)

Keep in mind that although urllib2 speaks https, it doesn't validate server certificates, so you might want to try and add-on package like pycurl or urlgrabber for better security. (I'm not sure if urlgrabber supports https.)

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