基本 Python StringIO —— 为什么 GetValue() 什么也不返回？
我遇到了基本的 python 问题。在下面的示例中，没有返回错误，但使用 pprint 显示所有变量的内容显示 contents is = '' ——为什么会出现这种情况？
import sys, os, re, StringIO, pprint, time
from BeautifulSoup import BeautifulSoup, BeautifulStoneSoup
import pycurl
url = "http://google.com/";
strio = StringIO.StringIO()
curlobj = pycurl.Curl()
curlobj.setopt(pycurl.URL, url)
curlobj.perform()
curlobj.close()
contents = strio.getvalue()
strio.close()
有什么想法吗？谢谢
I'm having basic python issues.. In the following example no errors are returned but displaying the contents of all variables using pprint shows that contents is = '' -- why would this possibly be the case?
import sys, os, re, StringIO, pprint, time
from BeautifulSoup import BeautifulSoup, BeautifulStoneSoup
import pycurl
url = "http://google.com/";
strio = StringIO.StringIO()
curlobj = pycurl.Curl()
curlobj.setopt(pycurl.URL, url)
curlobj.perform()
curlobj.close()
contents = strio.getvalue()
strio.close()
Any ideas? Thanks
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查看涉及
StringIO的行。这些语句都没有从
curlobj中提取内容。所以strio是空的。编辑（感谢@Alexander Cameron 和@agf）：
也许你的意思是
Look at the lines that involve
StringIO.None of these statements draw content from
curlobj. Sostriois empty.Edit (thanks to @Alexander Cameron and @agf):
Perhaps you meant
您永远不会对
strio变量执行任何操作。您必须将其传递给某个函数才能将任何内容写入其中。You never do anything with your
striovariable. You have to pass it in to some function in order for anything to get written to it.