如何将这个 python print 函数的每一行写入字符串列表？

发布于 2024-12-01 02:22:15 字数 350 浏览 0 评论 0原文

我有...

>>> for i in range(11):
...     for j in range(103):
...             print "./", '%02d' % i, "/IMG", '%04d' % j, ".jpg"
...
>>> (prints a whole bunch of lines representing files in a group of directories)

...而我想要的是将这些行中的小字符串和整数连接成单个字符串，并将其附加到一个包含大约 1100 个元素的列表，每个元素都是一个文件的名称。我该如何修改循环？

原文

I have...

>>> for i in range(11):
...     for j in range(103):
...             print "./", '%02d' % i, "/IMG", '%04d' % j, ".jpg"
...
>>> (prints a whole bunch of lines representing files in a group of directories)

...and what I want instead is to concatenate the little strings and ints in those lines into single strings, and append it to a list which will comprise approximately 1100 elements, each of which is the name of a file. How can I amend the loop?

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你列表最软的妹 2024-12-08 02:22:15

ITYM

l = []
for i in range(11):
    for j in range(103):
        l.append()

或者更短，

l = ['./%02d/IMG%04d.jpg' % (i, j) for i in range(11) for j in range(103)]

ITYM

l = []
for i in range(11):
    for j in range(103):
        l.append()

or, shorter,

l = ['./%02d/IMG%04d.jpg' % (i, j) for i in range(11) for j in range(103)]

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酒几许 2024-12-08 02:22:15

['./%02d/IMG%04d.jpg' % (i, j) for i in range(11) for j in xrange(103)]

['./%02d/IMG%04d.jpg' % (i, j) for i in range(11) for j in xrange(103)]

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公布 2024-12-08 02:22:15

from itertools import product
['./%02d/IMG%04d.jpg'%item for item in product(range(11),range(103))]

或稍快（~6%）但更混乱

 map('./%02d/IMG%04d.jpg'.__mod__, product(range(11),range(103)))

$ python -m timeit -s"from itertools import product" "['./%02d/IMG%04d.jpg'%item for item in product(range(11),range(103))]"
1000 loops, best of 3: 1.56 msec per loop

$ python -m timeit -s"from itertools import product" "map('./%02d/IMG%04d.jpg'.__mod__, product(range(11),range(103)))"
1000 loops, best of 3: 1.46 msec per loop

from itertools import product
['./%02d/IMG%04d.jpg'%item for item in product(range(11),range(103))]

or slightly(~6%) faster but more obfuscated

 map('./%02d/IMG%04d.jpg'.__mod__, product(range(11),range(103)))

$ python -m timeit -s"from itertools import product" "['./%02d/IMG%04d.jpg'%item for item in product(range(11),range(103))]"
1000 loops, best of 3: 1.56 msec per loop

$ python -m timeit -s"from itertools import product" "map('./%02d/IMG%04d.jpg'.__mod__, product(range(11),range(103)))"
1000 loops, best of 3: 1.46 msec per loop

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~没有更多了~