sed - 在纯文本文件中每第四行后插入一个逗号

发布于 2024-11-30 23:11:07 字数 472 浏览 2 评论 0原文

我试图使用 sed 在第 1、4、8 行等的值后面插入一个逗号，

sed '0-4 s/$/,/' in.txt > in2.txt

由于某种原因，这不起作用，所以我想知道是否有人有任何解决方案使用 awk、sed 或任何其他方法来执行此操作。

我收到的错误是

sed: 1: "0-4 s/$/,/": invalid command code -

当前我的数据如下所示：

        City
        Address
        Zip Code
        County

并且我试图将其格式化为这样

        City,
        Address
        Zip Code
        County

非常感谢。

原文

I am trying to insert a comma after the values on line 1, 4, 8, etc using sed,

sed '0-4 s/$/,/' in.txt > in2.txt

For some reason this isn't working so I was wondering if anyone has any solutions doing this using awk, sed, or any other methods.

The error I am getting is

sed: 1: "0-4 s/$/,/": invalid command code -

Currently my data looks like this:

        City
        Address
        Zip Code
        County

and I was trying to format it like this

        City,
        Address
        Zip Code
        County

Much Appreciated.

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谎言 2024-12-07 23:11:07

0-4 确实不是格式良好的 sed 语法。我会使用 awk 来实现此目的，但使用任何一个都可以轻松实现。

sed 's/$/,/;n;n;n' file

它替换一行并打印它，然后打印接下来的三行而不替换，然后从脚本的开头重新开始；或者

awk 'NR % 4 == 1 {sub(/$/,",")} {print}'

如果行号模 4 为 1，则进行替换，然后无条件打印。

Sed 的寻址模式有时有点令人失望；没有标准方法来计算相对于或参考文件末尾的行偏移。当然，awk 更复杂，但如果您只能学习其中之一，那么一定要选择 awk。（或者在当今时代，Python 或 Perl —— 更好的投资。）

0-4 indeed is not well-formed sed syntax. I would use awk for this, but it is easy to do it with either.

sed 's/$/,/;n;n;n' file

which substitutes one line and prints it, then prints the next three lines without substitution, then starts over from the beginning of the script; or

awk 'NR % 4 == 1 {sub(/$/,",")} {print}'

which does the substitution if the line number modulo 4 is 1, then prints unconditionally.

Sed's addressing modes are sometimes a tad disappointing; there is no standard way to calculate line offsets, relative or in reference to e.g. the end of the file. Of course, awk is more complex, but if you can only learn one or the other, definitely go for awk. (Or in this day and age, Python or Perl -- a much better investment.)

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