super() 不允许我使用参数调用超级构造函数

发布于 2024-11-30 17:30:48 字数 885 浏览 2 评论 0原文

我想调用带有两个参数的超类构造函数，因此我调用 super(arguments)，但编译器说：

“类 Person 中的构造函数 Person 不能应用于给定类型；
必需：无参数
找到：Java.lang.String、int
原因：实际参数列表和正式参数列表的长度不同”

我不知道为什么会发生这种情况。对 super 的调用是第一行。参数匹配（但由于某种原因不匹配编译器）。有人知道发生了什么吗？

顺便说一句，我正在使用 NetBeans。

编辑：我卸载了 NetBeans，安装了 Eclipse，现在一切正常，我不知道，也永远不会知道为什么 NetBeans 给我一个错误。为了你的帮助。

public class Person
 {
 private String name;
 private int age;


 public Person() { name = " "; age = 0; }
 public Person(String nm, int ag) { name = nm; age = ag; }
 }


 public class BaseballPlayer extends Person
  {
  private int homeruns;
  private double bat_avg;


  BaseballPlayer()
  {
  super();
  homeruns = 0;
  bat_avg = 0;
  }

  BaseballPlayer(String name, int age, int hr, double bavg)
  {
  super(name, age); // THIS CAUSES AN ERROR. I DON'T KNOW WHY
  homeruns = hr;
  bat_avg = bavg;
  }
 }

原文

I want to call the super class' constructor that takes two arguments, so I call super(arguments), but the compiler says:

"Constructor Person in class Person cannot be applied to given types;
required: no arguments
Found: Java.lang.String, int
reason: actual and formal argument lists differ in length"

I have no clue why this is happening. The call to super is the first line. The arguments match (but not to the compiler for some reason). Does anyone know what's going on?

I'm using NetBeans, by the way. The latest version.

EDIT: I uninstalled NetBeans, installed Eclipse, and now everything works perfectly. I don't know, nor will I ever know, why NetBeans gave me an error. Thanks everyone for your help.

public class Person
 {
 private String name;
 private int age;


 public Person() { name = " "; age = 0; }
 public Person(String nm, int ag) { name = nm; age = ag; }
 }


 public class BaseballPlayer extends Person
  {
  private int homeruns;
  private double bat_avg;


  BaseballPlayer()
  {
  super();
  homeruns = 0;
  bat_avg = 0;
  }

  BaseballPlayer(String name, int age, int hr, double bavg)
  {
  super(name, age); // THIS CAUSES AN ERROR. I DON'T KNOW WHY
  homeruns = hr;
  bat_avg = bavg;
  }
 }

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陌路终见情 2024-12-07 17:30:48

顺便说一句，恕我直言，这样做是更好的形式：

public class Person
    ...
    public Person() { 
        this("", 0); // No-args constructor calls the arg'd version with default values
    }

    public Person(String nm, int ag) {
        name = nm;
        age = ag;
    }
    ...
}

这意味着一切都通过一个构造函数。如果您必须在构造函数中添加任何内容，则只有一处可以进行更改。

btw, IMHO it's better form, to do this:

public class Person
    ...
    public Person() { 
        this("", 0); // No-args constructor calls the arg'd version with default values
    }

    public Person(String nm, int ag) {
        name = nm;
        age = ag;
    }
    ...
}

This means everything goes through the one constructor. If you have to add anything into your constructor, you have only one place to do change.

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