使用 XpathNavigator 和 HtmlAgilityPack 查找 InnerHtml 值

发布于 2024-11-30 17:27:45 字数 1031 浏览 3 评论 0原文

test.xml 的一部分

<tr class="a"> 
    <td align="left" nowrap="true">desc1</td> 
    <td align="left">desc2</td>  
    <td>desc3</td>  
    <td align="left">desc4</td> 
    <td align="left">desc5</td>
    <td>desc6</td> 
    <td>desc7</td> 
    <td>desc8</td>
    <td class="nr">desc9</td>
</tr>

//create XpathNavigator to get the last value inside td ie desc9

> HtmlDocument document = new HtmlDocument();
        document.Load(Server.MapPath("test.xml"));

        XPathNavigator xPathNavigator = document.CreateNavigator();
        object o = xPathNavigator.Evaluate("/table[1]/tbody[1]/tr[2]/td[9]");

调试器显示可以按如下方式计算该值，这非常麻烦。

((HtmlAgilityPack.HtmlNodeNavigator)((new System.Linq.SystemCore_EnumerableDebugView(((MS.Internal.Xml.XPath.XPathSelectionIterator)(o)))).Items[0])).Value

前往 desc9 的最佳方式是什么？

原文

portion of test.xml

<tr class="a"> 
    <td align="left" nowrap="true">desc1</td> 
    <td align="left">desc2</td>  
    <td>desc3</td>  
    <td align="left">desc4</td> 
    <td align="left">desc5</td>
    <td>desc6</td> 
    <td>desc7</td> 
    <td>desc8</td>
    <td class="nr">desc9</td>
</tr>

//create XpathNavigator to get the last value inside td i.e. desc9

> HtmlDocument document = new HtmlDocument();
        document.Load(Server.MapPath("test.xml"));

        XPathNavigator xPathNavigator = document.CreateNavigator();
        object o = xPathNavigator.Evaluate("/table[1]/tbody[1]/tr[2]/td[9]");

The debugger shows the value can be evaluated as below which is very cumbersome.

((HtmlAgilityPack.HtmlNodeNavigator)((new System.Linq.SystemCore_EnumerableDebugView(((MS.Internal.Xml.XPath.XPathSelectionIterator)(o)))).Items[0])).Value

What is the best way to get to desc9?

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深巷少女 2024-12-07 17:27:45

我没有使用过 XPathNavigator，但这里有一个类似的解决方案，具有 SelectNodes/SelectSingleNode 样式和 HTML Agility Pack。

string xPathSearch = "/table[1]/tbody[1]/tr[2]";
HtmlNode tableRow = doc.DocumentNode.SelectSingleNode(xPathSearch);
string description9 = tableRow.ChildNodes[9].InnerText;

仅供

string xPathSearch = "/table[1]/tbody[1]/tr[2]/td[9]";
HtmlNode tableColumn = doc.DocumentNode.SelectSingleNode(xPathSearch);
string description9 = tableColumn.InnerText;

参考 - 关于 HTML Agility 包的最佳文档似乎是源代码中包含的示例。不知道为什么这不是文档中的单独下载。

I haven't used the XPathNavigator but here is a similar solution with the SelectNodes/SelectSingleNode style and the HTML Agility Pack.

string xPathSearch = "/table[1]/tbody[1]/tr[2]";
HtmlNode tableRow = doc.DocumentNode.SelectSingleNode(xPathSearch);
string description9 = tableRow.ChildNodes[9].InnerText;

string xPathSearch = "/table[1]/tbody[1]/tr[2]/td[9]";
HtmlNode tableColumn = doc.DocumentNode.SelectSingleNode(xPathSearch);
string description9 = tableColumn.InnerText;

FYI - The best documentation on the HTML Agility pack seems to be the samples included with the Source. Not sure why that isn't a separate download in the documentation.

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歌入人心 2024-12-07 17:27:45

像这样的东西：

/table[1]/tbody[1]/tr[@class="a"]/td[last()]

看看 XPath 语法

something like this:

/table[1]/tbody[1]/tr[@class="a"]/td[last()]

Take a look at XPath Syntax

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风吹短裙飘 2024-12-07 17:27:45

我认为你的做法是错误的。

我相信您需要做的只是以下内容：

document.DocumentNode.SelectSingleNode("/table[1]/tbody[1]/tr[2]/td[9]");

我找不到文档的在线副本来链接您，但您可以检查 http://htmlagilitypack.codeplex.com/releases/view/44954 了解更多详细信息。

另外，如果您只是阅读 XML，那么您使用 html 敏捷包是否有任何原因，或者只是您的测试文件是有效的 XML？

I think you are going about this wrong.

I believe all you should need to do is something along the lines of:

document.DocumentNode.SelectSingleNode("/table[1]/tbody[1]/tr[2]/td[9]");

I can't find an online copy of the docs to link you to but you can check the docs found at http://htmlagilitypack.codeplex.com/releases/view/44954 for more details.

Also if you are just reading XML is there any reason why you are using the html agility pack or is it just your test file that is valid XML?

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