在关联数组内搜索和替换

Question

我需要在关联数组内搜索和替换。

例如：

$user = "user1"; // I've updated this

$myarray = array("user1" => "search1", "user2" => "search2", "user3" => "search1" ) ;

我想将 search1 替换为 search4。我怎样才能实现这个目标？

更新：我忘记提及该数组有多个 search1 值，我只想更改 key == $user 处的值。抱歉没有早点提到这一点。

Answer 1

更新

自从帖子更新后，我有机会睡一觉，我意识到我的回答很愚蠢。如果您有给定的键并且需要更改它的值，为什么要迭代整个数组呢？

$user    = 'user1';
$search  = 'search1';
$replace = 'search4';
$array   = array('user1' => 'search1', 'user2' => 'search2');

if (isset($array[$user]) && $search === $array[$user]) $array[$user] = $replace;

---

与 @Joseph 的方法类似（几乎相同），但有一些调整：

$user = 'user1';
$array = array("user1" => "search1", "user2" => "search2" );

foreach($array as $key => &$value) {
    if ($key === $user) {
        $value = 'search4';
        break; // Stop iterating after key has been found
    }
}

通过引用传递是在 foreach 内编辑的更好方法，并且可以说更快。

Answer 2

在关联数组或数字中搜索和替换
替换任何关联数组中的值，并且数组可以是任何深度

function array_value_replace($maybe_array, $replace_from, $replace_to) {

    if (!empty($maybe_array)) {
        if (is_array($maybe_array)) {
            foreach ($maybe_array as $key => $value) {
                $maybe_array[$key] = array_value_replace($value, $replace_from, $replace_to);
            }
        } else {
            if(is_string($maybe_array)){
                $maybe_array = str_replace($replace_from, $replace_to, $maybe_array);
            }               
        }
    }

    return $maybe_array;
}

Answer 3

如果您想要特定的密钥，那么您只需在前面的示例中添加密钥条件即可。

$user = "user1";
$myarray = array("user1" => "search1", "user2" => "search2" );

foreach($myarray as $key => $val)
{
    if ($val == 'search1' && $key == $user) $myarray[$key] = 'search4';
}

Answer 4

使用 str_replace 应该可以：

$myarray = array("user1" => "search1", "user2" => "search2" ) ;

$newArray = str_replace('search1', 'search4', $myarray);

Answer 5

根据约瑟夫的回答，使用 preg_replace 可能会启用您可以在其他情况下使用该代码：

function pregReplaceInArray($pattern,$replacement,$array) {
    foreach ($array as $key => $value) {
        $array[$key] = preg_replace($pattern,$replacement,$value);
    }   
    return $array;
}

Answer 6

$myarray = array("user1" => "search1", "user2" => "search2" );

foreach($myarray as $key => $val)
{
    if ($val == 'search1') $myarray[$key] = 'search4';
}

Answer 7

有一个函数可以实现此目的：array_map()。

// Using a lamba function, PHP 5.3 required
$newarray = array_map(
    function($v) { if ($v == 'search1') $v = 'search4'; return $v; },
    $myarray
);

如果您不想使用 lambda 函数，请定义一个普通函数或方法并对其进行回调。

Answer 8

为什么不直接做

if (isset($myarray[$user])) $myarray[$user] = 'search4';

Answer 9

$user = "user1";
$myarray = array("user1" => "search1", "user2" => "search2", "user3" => "search1" );
foreach($myarray as $key => $val)
{
    if ($val == 'search1' and $key == $user )
    {
       $myarray[$key] = 'search4';
       break;
    }
}
print_r($myarray);

印刷：

Array
(
    [user1] => search4
    [user2] => search2
    [user3] => search1
)

Answer 10

$originalArray = array( "user1" => "search1" , "user2" => "search2" );
$pattern = 'search1';
$replace = 'search4';

$replacedArray = preg_replace( '/'.$pattern.'/' , $replace , $originalArray );

修复了响应此解决方案