如何将 .txt 文件放入数据源？

Question

可能的重复：
将 .txt 文件放入 DataGridView

当我单击打开按钮时我想选择一个文件并将其放入 DataSource 中，以便进一步在 DataGridView 中使用。

现在我的内容看起来像这样：

OpenFileDialog openFile = new OpenFileDialog();

openFile.DefaultExt = "*.txt";
openFile.Filter = ".txt Files|*.txt";
openFile.RestoreDirectory = true;

try
{
    if (openFile.ShowDialog() == DialogResult.OK && openFile.FileName.Length > 0)
    {
        // Right now I am loading the file into a RichTextBox
        openFileRTB.LoadFile(openFile.FileName, RichTextBoxStreamType.PlainText);

        // What I would like to do is load it into a DataSource and then into a DataGridView.
        // So really I would like to remove the openFileRTB line of code and replace it.
        // That is where I need help :).
    }
}

catch (Exception)
{
    MessageBox.Show("There was not a specified file path to open.", "Path Not Found Error", MessageBoxButtons.OK, MessageBoxIcon.Warning);
}

这是我要打开的文件的示例（以空格分隔）：

Title1 Title2 Title3 Title4 Title5 Title6
abc123 abc123-123-123 225.123 123.456 180 thing99
c123 somethingHERE 987.123 123.456 360 anotherThing1
abc124 somethingHERE225.123 123.456 0 thing99

我对 DataSource 和 DataGridView 非常不熟悉，所以如果我可以获得一些关于它如何工作、需要发生什么、它看起来如何等方面的帮助，我们将不胜感激。 ：）

谢谢。

Answer 1

您可以分割行并循环所有行/列以生成数据表：

例如（VB.NET）：

Dim separator = " "c
Dim fileName = OpenFileDialog1.FileName
Dim tbl As New DataTable(fileName)
Dim query = From line In IO.File.ReadAllLines(fileName)
            Let row = line.Split(separator)

If query.Any Then
   For Each col In query(0).row
         'build DataColumns from first line'
         tbl.Columns.Add(New DataColumn(col))
   Next
   If query.Count > 1 Then
       For rowIndex = 1 To query.Count - 1
           Dim newRow = tbl.NewRow
           For colIndex = 0 To query(rowIndex).row.Length - 1
               Dim colValue = query(rowIndex).row(colIndex)
               newRow(colIndex) = colValue
           Next
           tbl.Rows.Add(newRow)
       Next
   End If
End If

这在没有 LINQ 的情况下也能正常工作（现在也在 C# 中;)）：

....
var rows = System.IO.File.ReadAllLines(fileName);
if (rows.Length != 0) {
    foreach (string headerCol in rows(0).Split(separator)) {
        tbl.Columns.Add(new DataColumn(headerCol));
    }
    if (rows.Length > 1) {
        for (rowIndex = 1; rowIndex < rows.Length; rowIndex++) {
            var newRow = tbl.NewRow();
            var cols = rows(rowIndex).Split(separator);
            for (colIndex = 0; colIndex < cols.Length; colIndex++) {
                newRow(colIndex) = cols(colIndex);
            }
            tbl.Rows.Add(newRow);
        }
    }
}