使用 StringTokenizer 输入 5 个整数

发布于 2024-11-30 10:25:20 字数 671 浏览 5 评论 0原文

下面是部分代码。

import java.io.*;
import java.util.*;
public class inputting {
public static void main(String[] args) throws IOException {
    // TODO Auto-generated method stub
    int i,j;

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
     System.out.println("enter numbers??");
     String str = br.readLine();
     StringTokenizer tokenizer = new StringTokenizer(str);
     j=Integer.parseInt(tokenizer);
}
}

现在我不知道 StringTokenizer 会去哪里，也不知道我到目前为止所做的是否正确。但基本上我希望用户请求 5 个整数，然后打印它。

如何从字符串中取出整数？如果有人能为我完成代码，我将非常感激。

PS这不是作业问题，我正在学习面向对象编程而不是Java。所以我们的教授并没有足够的热情来教我们完整的Java语法。

原文

Below is the partial code.

import java.io.*;
import java.util.*;
public class inputting {
public static void main(String[] args) throws IOException {
    // TODO Auto-generated method stub
    int i,j;

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
     System.out.println("enter numbers??");
     String str = br.readLine();
     StringTokenizer tokenizer = new StringTokenizer(str);
     j=Integer.parseInt(tokenizer);
}
}

Now I don't know where would StringTokenizer go and whether what I have done till now is correct or not. But basically I want user to ask for 5 integers and then let say just print it.

How do I take the integers out of the strings? If someone could complete the code for me, I would really appreciate.

P.S. This is not a homework question, I am learning object oriented programming and not Java. So our professor didn't care enough to teach us the syntax of Java completely.

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烟若柳尘 2024-12-07 10:25:20

您可以使用 StringTokenizer 使用指定的分隔符将字符串分解为多个字符串（或标记）。

例如：

String sample = "1,2,3,4,5";
StringTokenizer tokenizer = new StringTokenizer(sample,",");

while(tokenizer.hasMoreTokens()) {
  int convertedToInt = Integer.parseInt(tokenizer.nextToken());
}

注意：没有运行这个，可能包含语法错误，但你明白了。

StringTokenizer JavaDoc 在这里： http://download.oracle .com/javase/1.4.2/docs/api/java/util/StringTokenizer.html

You would use StringTokenizer to break up a string into multiple strings(or tokens) using a specified delimiter.

For example:

String sample = "1,2,3,4,5";
StringTokenizer tokenizer = new StringTokenizer(sample,",");

while(tokenizer.hasMoreTokens()) {
  int convertedToInt = Integer.parseInt(tokenizer.nextToken());
}

Note: didn't run this, might contain syntax error, but you get the idea.

StringTokenizer JavaDoc here: http://download.oracle.com/javase/1.4.2/docs/api/java/util/StringTokenizer.html

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べ繥欢鉨o。 2024-12-07 10:25:20

您可能会发现使用字符串的 split() 方法更容易。

import java.io.*;
import java.util.*;
public class inputting {
public static void main(String[] args) throws IOException {
    // TODO Auto-generated method stub
    int i,j;

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
     System.out.println("enter numbers??");
     String str = br.readLine();
     String[] nums = str.split(" "); //returns an array of strings split based on the parameter
     i = Integer.parseInt(nums[0]);
     j = Integer.parseint(nums[1]);
}
}

这条线
j=Integer.parseInt(tokenizer);
无法编译，StringTokenizer 不是字符串。
j=Integer.parseInt(tokenizer.nextToken());
会编译，因为这是一个字符串，因此请随意使用它，而不是上面使用 String 类中的 split() 方法的代码。

You may find it easier to use a string's split() method.

import java.io.*;
import java.util.*;
public class inputting {
public static void main(String[] args) throws IOException {
    // TODO Auto-generated method stub
    int i,j;

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
     System.out.println("enter numbers??");
     String str = br.readLine();
     String[] nums = str.split(" "); //returns an array of strings split based on the parameter
     i = Integer.parseInt(nums[0]);
     j = Integer.parseint(nums[1]);
}
}

the line
j=Integer.parseInt(tokenizer);
will not compile, a StringTokenizer is not a string.
j=Integer.parseInt(tokenizer.nextToken());
will compile because that is a string, so feel free to use that rather than the code presented above that uses the split() method from the String class.

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