创建具有自定义文件扩展名的新文件？
如何创建文件格式为 .kuy 的新文件。该文件将保存加密数据。然后我可以选择扩展名为 .kuy 的文件进行解密。因此，如果我加密了 soundfile.aup，加密的文件将为 soundfile.aup.kuy，然后用户将继续解密该文件，在这种情况下，输出将为 soundfile.aup。
谢谢你，
鲍比
How can I create a new file with a file format of say .kuy.This file would be holding encrypted data. And then later I could choose that file with extension .kuy to decrypt. So if I encrypted soundfile.aup, the encrypted file would be soundfile.aup.kuy, then the user would proceed to decrypting that file in which case the output would be soundfile.aup.
Thank you,
Bobby
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您可以通过转到 Target 的信息窗口并选择“属性”选项卡来为应用程序分配文件扩展名：
之后也就是说，您只需在保存文件时添加所需的扩展名即可。
You can assign a file extension to your application by going to your Target's info window and selecting the Properties tab:
After that, you just need to add your desired extension when you save a file.
正如史蒂夫建议的那样，首先您必须创建自定义文件格式。之后，每当打开自定义文件时（双击或其他任何方式），其路径将被传递到 application:openFile:。 http://developer.apple.com/library/mac/documentation/Cocoa/Reference/NSApplicationDelegate_Protocol/Reference/Reference.html#//apple_ref/doc/uid/TP40008592-CH1-SW29
一旦你找到了路径，按照你的逻辑去做，你应该没问题。
As Steve suggests, first you have to create a custom file format. After that, whenever a custom file gets open - double click or whatever - its path will be passed to application:openFile:. http://developer.apple.com/library/mac/documentation/Cocoa/Reference/NSApplicationDelegate_Protocol/Reference/Reference.html#//apple_ref/doc/uid/TP40008592-CH1-SW29
Once you have the path, do your logic and you should be fine.