在 Web 服务中返回 java.util.List

发布于 2024-11-30 00:18:26 字数 991 浏览 5 评论 0原文

我尝试在 eclipse 中创建一个自下而上的 Java bean Web 服务，我需要返回一个 java.util.List，所以我在服务器上有这个

public class BookStoreWS {
    private Book book1;
    private List<Book> listOfBooks;

    public Book getBook(){
        return  book1;
    }
    public List<Book> getBooks(){
        return  listOfBooks;
    }
}

，在客户端上有这个

public static void main(String[] args) {
    BookStoreWSStub stub = new BookStoreWSStub();
    GetBookResponseDocument gbrd = stub.getBook();
    Book book = gbrd.getGetBookResponse().getReturn();//OK

    GetBooksResponseDocument gbrd2 = stub.getBooks();
    XmlObject OMGIAMNOTALIST = gbrd2.getGetBooksResponse().getReturn();//BAD
}

，所以 getBook() 返回我想要的对象 Book 但 getBooks() 返回 XmlObject 而不是 List

任何简单的方法可以获得List 而不是 XmlObject？或者将 XmlObject 转换为 List？

原文

I try to create a Bottom up Java bean Web Service in eclipse and I need to return a java.util.List so I have this on the server

public class BookStoreWS {
    private Book book1;
    private List<Book> listOfBooks;

    public Book getBook(){
        return  book1;
    }
    public List<Book> getBooks(){
        return  listOfBooks;
    }
}

and this on the client

public static void main(String[] args) {
    BookStoreWSStub stub = new BookStoreWSStub();
    GetBookResponseDocument gbrd = stub.getBook();
    Book book = gbrd.getGetBookResponse().getReturn();//OK

    GetBooksResponseDocument gbrd2 = stub.getBooks();
    XmlObject OMGIAMNOTALIST = gbrd2.getGetBooksResponse().getReturn();//BAD
}

So getBook() returns my desired object Book but getBooks() returns XmlObject instead of a List<Book>

Any easy way of getting a List<Book> instead of a XmlObject? Or to transform the XmlObject into a List<Book>?

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假扮的天使 2024-12-07 00:18:26

这就是您要找的吗？

List<A> OMGIAMALIST = new ArrayList<A>();
OMGIAMALIST.addAll(stub.getAs());

for ( A item : OMGIAMALIST ) {
    XmlObject OMGIAMANITEM = item.getGetAsResponse().getReturn();
}

XmlObject （很可能）不能是 A，但 item 肯定是。

Is that what you are looking for?

List<A> OMGIAMALIST = new ArrayList<A>();
OMGIAMALIST.addAll(stub.getAs());

for ( A item : OMGIAMALIST ) {
    XmlObject OMGIAMANITEM = item.getGetAsResponse().getReturn();
}

XmlObject (most probably) cannot be an A, but item surely is.

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